Chapter 4: Problem 55
Sketch the graph of the equation. (a) Estimate \(y\) if \(x=40 .(\text { b ) Estimate } x \text { if } y=2\) $$y=(1.085)^{x}$$
Short Answer
Expert verified
For \( x = 40 \), \( y \approx 27.90 \). For \( y = 2 \), \( x \approx 8.14 \).
Step by step solution
01
Understanding the Equation
The given equation is an exponential function: \( y = (1.085)^{x} \). This equation represents how \( y \) grows as \( x \) increases. The base of the exponent, 1.085, indicates growth because it is greater than 1.
02
Estimating y for x=40
To estimate \( y \) when \( x = 40 \), plug 40 into the equation: \[ y = (1.085)^{40} \]. Calculating this gives approximately \( y \approx 27.90 \).
03
Estimating x for y=2
To estimate \( x \) when \( y = 2 \), set up the equation: \( (1.085)^{x} = 2 \). Taking the logarithm of both sides, we apply the formula: \( x = \frac{\log(2)}{\log(1.085)} \). Solving this, we find \( x \approx 8.14 \).
04
Sketching the Graph
The graph of \( y = (1.085)^{x} \) is an exponential growth curve starting from \( (0,1) \) and rising steadily. The calculations from Steps 2 and 3 help confirm where \( x = 40 \) and \( y = 2 \) occur on this curve.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Exponential Functions
When you graph an exponential function like \( y = (1.085)^{x} \), you are looking at a curve that shows a specific kind of growth. This function starts at the point \((0,1)\), meaning when \( x = 0 \), \( y \) is always 1, because any number raised to the power of zero is 1. As \( x \) increases, the value of \( y \) increases exponentially. This results in a rapid upward curve after a certain point, especially as the base of the exponent is slightly greater than 1.
To sketch this graph, start placing points using various values of \( x \), such as \( x = 0, 10, 20 \), and even the given problems like \( x = 40 \). As you plot these, you'll notice how quickly the values rise. The graph will steadily slope upward and never touch the x-axis, indicating it's always positive.
This quick rise is characteristic of exponential functions, where even small increases in \( x \) lead to large increases in \( y \). Understanding this helps you predict the behavior of exponential growth functions in real-world situations, such as population growth or compound interest.
To sketch this graph, start placing points using various values of \( x \), such as \( x = 0, 10, 20 \), and even the given problems like \( x = 40 \). As you plot these, you'll notice how quickly the values rise. The graph will steadily slope upward and never touch the x-axis, indicating it's always positive.
This quick rise is characteristic of exponential functions, where even small increases in \( x \) lead to large increases in \( y \). Understanding this helps you predict the behavior of exponential growth functions in real-world situations, such as population growth or compound interest.
Exponentiation
Exponentiation involves raising a base number to the power of an exponent, like in \((1.085)^{x}\). Here, 1.085 is the base, and \( x \) is the exponent. The exponent tells you how many times to multiply the base number by itself.
The base value is crucial in determining the function’s nature:
The base value is crucial in determining the function’s nature:
- If the base is greater than 1, the function will depict exponential growth, leading to a rapidly increasing line.
- If the base is less than 1, the function will show exponential decay, where the curve will move downward as \( x \) increases.
Logarithms
Logarithms are the inverse operations of exponentiation, which means they answer the question: "To what exponent must we raise the base to get a specific number?" When you encounter a situation like solving for \( x \) in \((1.085)^{x} = 2\), you need logarithms to find \( x \).
Using the logarithm function, you can rearrange the equation:
Using the logarithm function, you can rearrange the equation:
- Take the logarithm of both sides: \( \log((1.085)^{x}) = \log(2) \).
- Use the logarithm power rule to simplify: \( x \cdot \log(1.085) = \log(2) \).
- Solve for \( x \): \( x = \frac{\log(2)}{\log(1.085)} \).