/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Sketch the graph of \(f,\) and u... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of \(f,\) and use the change of base formula to approximate the \(x\) -intercept. $$f(x)=3^{x}-6$$

Short Answer

Expert verified
The x-intercept is approximately 1.63.

Step by step solution

01

Understand the Function

The function given is \( f(x) = 3^x - 6 \). This is an exponential function where the base is 3, and it has been shifted down by 6 units.
02

Determine the Horizontal Asymptote

For an exponential function of the form \( a^x + c \), the horizontal asymptote is \( y = c \). Here, \( c = -6 \), so the horizontal asymptote is \( y = -6 \).
03

Determine the x-intercept

To find the \( x \)-intercept, set \( f(x) = 0 \) and solve for \( x \):\[3^x - 6 = 0\]\[3^x = 6\]
04

Use the Change of Base Formula

To solve \( 3^x = 6 \), take the log of both sides and use the change of base formula:\[x = \log_3{6} = \frac{\ln{6}}{\ln{3}}\]Now calculate this value using a calculator.
05

Calculate the x-intercept

Using a calculator, evaluate \( \ln{6} \approx 1.79176 \) and \( \ln{3} \approx 1.09861 \). Thus,\[x \approx \frac{1.79176}{1.09861} \approx 1.63093\]
06

Sketch the Graph

Plot the horizontal asymptote at \( y = -6 \). The function will pass through the \( x \)-intercept at \( x \approx 1.63 \). Since \( f(x) \) is an increasing exponential function, draw the curve starting from close to the asymptote on the left side and increasing through the intercept.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Change of Base Formula
The change of base formula is a handy tool for solving exponential equations, especially when calculators are involved. It allows us to convert a logarithm of any base into a simpler expression involving the natural logarithm (ln) or logarithms of base 10.
This is extremely useful when solving equations like \[ 3^x = 6. \]To find the value of \( x \), you can take the log of both sides. Using the change of base formula, we convert the base 3 logarithm into natural logarithms:
\[ x = \log_3{6} = \frac{\ln{6}}{\ln{3}}. \]
This step simplifies calculations, as most calculators can easily compute natural logarithms. It is a core technique in logarithm problems, making the solutions more accessible.
X-Intercept Approximation
The x-intercept of a function is where the graph crosses the x-axis. This is a crucial point to approximate because it gives valuable insight into the behavior of the exponential function.
To find the x-intercept of the function \( f(x) = 3^x - 6 \), set \( f(x) = 0 \). You solve the equation \[ 3^x - 6 = 0 \] which simplifies to \[ 3^x = 6. \]
Using the change of base formula, you can approximate the x-intercept as:
\[ x \approx \frac{\ln{6}}{\ln{3}} = 1.63093. \]
Calculating this on a calculator ensures precision in sketching and understanding the function.
Horizontal Asymptote
A horizontal asymptote in a function is a line that the graph approaches but never quite reaches as \( x \) moves towards positive or negative infinity.
In the exponential function \( f(x) = 3^x - 6 \), the horizontal asymptote is defined by the constant term in the equation. For this form, \( y = c \), so our asymptote is \( y = -6 \).
Understanding this line helps predict the behavior of the graph, especially for large or very negative \( x \) values, where the curve gets extremely close to this line without touching it.
Graph Sketching of Functions
Sketching the graph of exponential functions requires understanding their transformations, intercepts, and asymptotes. These elements provide a roadmap for drawing a precise graph. Begin by marking the horizontal asymptote \( y = -6 \). This is a guide for how the graph behaves at extremes.
Next, find the x-intercept, approximately \( x = 1.63 \), where \( f(x) = 0 \). This point is crucial, as the graph will pass through it.
For the function \( f(x) = 3^x - 6 \), start sketching close to the asymptote on the left and let the curve increase as it moves right, passing through the x-intercept.
  • Mark the horizontal asymptote as a dashed line.
  • Plot the x-intercept.
  • Draw a smooth exponential curve rising from left to right.
This visual aid reinforces the understanding of how exponential functions behave.

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Most popular questions from this chapter

In a survey of 15 cities ranging in population \(P\) from 300 to \(3,000,000,\) it was found that the average walking speed \(S\) (in \(\mathrm{ft} / \mathrm{sec}\) ) of a pedestrian could be approximated by \(S=0.05+0.86 \log P\) (a) How does the population affect the average walking speed? (b) For what population is the average walking speed \(5 \mathrm{ft} / \mathrm{sec} ?\)

The population \(N(t)\) (in millions) of the United States \(t\) years after 1980 may be approximated by the formula \(N(t)=231 e^{11,013t}.\) When will the population be twice what it was in \(1980?\)

Exer. \(69-70\) : Bird calls decrease In intensity (loudness) as they travel through the atmosphere. The farther a bird is from an observer, the softer the sound. This decrease in intensity can be used to estimate the distance between an observer and a bird. A formula that can be used to measure this distance is $$ \boldsymbol{I}=\boldsymbol{I}_{\mathbf{0}}-\boldsymbol{2 0} \log \boldsymbol{d}-\boldsymbol{k} \boldsymbol{d} \quad \text { provided } \quad \mathbf{0} \leq \boldsymbol{I} \leq \boldsymbol{I}_{\mathbf{\theta}} $$ where \(I_{0}\) represents the intensity (in decibels) of the bird at a distance of one meter \(\left(I_{0}\) is often known and usually de- \right. pends only on the type of bird), \(I\) is the observed intensity at a distance \(d\) meters from the bird, and \(k\) is a positive constant that depends on the atmospheric conditions such as temperature and humidity. Given \(I_{0 n} I,\) and \(k,\) graphically estimate the distance \(d\) between the bird and the observer. $$I_{0}=60, \quad I=15, \quad k=0.11$$

Approximate the function at the value of \(x\) to four decimal places. (a) \(f(x)=\log \left(2 x^{2}+1\right)-10^{-x}, \quad x=1.95\) (b) \(g(x)=\frac{x-3.4}{\ln x+4}, \quad x=0.55\)

Graph \(f\) on the given interval. (a) Estimate the largest interval \([a, b]\) with \(a < 0 < b\) on which \(f\) is one-to-one. (b) If \(g\) is the function with domain \([a, b]\) such that \(g(x)=f(x)\) for \(a \leq x \leq b,\) estimate the domain and range of \(g^{-1}\). $$f(x)=2.1 x^{3}-2.98 x^{2}-2.11 x+3 ; \quad[-1,2]$$

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