Chapter 4: Problem 45
Sketch the graph of \(f,\) and use the change of base formula to approximate the \(x\) -intercept. $$f(x)=4^{x}-3$$
Short Answer
Expert verified
The function has an x-intercept at approximately 0.793.
Step by step solution
01
Analyze the Function
The function given is \( f(x) = 4^x - 3 \). This function is an exponential function shifted downward by 3 units. The basic structure of the function is \( g(x) = 4^x \). This function naturally passes through (0,1) when no shifts are applied.
02
Determine Asymptotes and Intercepts
For \( f(x) = 4^x - 3 \), the horizontal asymptote is \( y = -3 \), because as \( x \to -\infty \), \( 4^x \to 0 \) and hence \( f(x) \to -3 \).To find the \( y \)-intercept, set \( x = 0 \):\[ f(0) = 4^0 - 3 = 1 - 3 = -2. \] Thus, the \( y \)-intercept is at (0,-2).
03
Use the Change of Base Formula
The \( x \)-intercept is where \( f(x) = 0 \). Setting \( 4^x - 3 = 0 \):\[ 4^x = 3. \]To solve \( 4^x = 3 \), use the change of base formula:\[ x = \frac{\log 3}{\log 4}. \]
04
Calculate the Logarithmic Expression
Using a calculator, approximate \( \log 3 \approx 0.4771 \) and \( \log 4 \approx 0.6021 \). So,\[ x \approx \frac{0.4771}{0.6021} \approx 0.7925. \]Thus, the \( x \)-intercept is approximately \( x \approx 0.7925 \).
05
Sketch the Graph
Draw the exponential curve passing through the point (0,-2) with a horizontal asymptote at \( y = -3 \). Make sure the curve approaches \( y = -3 \) as \( x \to -\infty \) and rises steeply as \( x \) increases. Mark the point where \( x \approx 0.7925 \) as the \( x \)-intercept on the graph.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Change of Base Formula
The change of base formula is a useful tool for solving exponential equations where the base isn't easily interpretable by common logarithms or natural logarithms. It is especially handy when evaluating exponential functions like \(4^x = 3\).
To employ the change of base formula, rewrite the expression as:
The expression we obtain tells us how to find \(x\) by simply dividing the logarithm of the target by the logarithm of the base. This gives us a specific numerical approximation for the \(x\)-intercept of exponential graphs, which can be crucial when precise calculations are needed.
To employ the change of base formula, rewrite the expression as:
- \(x = \frac{\log 3}{\log 4}\).
The expression we obtain tells us how to find \(x\) by simply dividing the logarithm of the target by the logarithm of the base. This gives us a specific numerical approximation for the \(x\)-intercept of exponential graphs, which can be crucial when precise calculations are needed.
Graphing Techniques
When graphing exponential functions, it's helpful to analyze transformations and intercepts to get a cleaner picture of the graph. Take the function \(f(x) = 4^x - 3\) as an example.
The first step is recognizing the function's core, \(4^x\). This is an exponential function naturally curving upwards and passing through the point (0,1).
Additional details include transformations:
The first step is recognizing the function's core, \(4^x\). This is an exponential function naturally curving upwards and passing through the point (0,1).
Additional details include transformations:
- This particular function shifts downward by 3 units, moving the graph from its original position to approach the horizontal line \(y = -3\).
- The \(y\)-intercept for this transformed graph is calculated by plugging \(x = 0\) into \(4^x - 3\), giving us the point (0,-2).
- Start by marking the \(y\)-intercept on your graph.
- Sketch the curve reflecting the exponential growth as \(x\) increases.
- Make sure the graph never crosses below \(y = -3\).
Asymptotes in Graphs
Asymptotes are lines that a graph approaches but never actually touches. For the function \(f(x) = 4^x - 3\), the horizontal asymptote is \(y = -3\).
This occurs because as \(x\) tends towards negative infinity, \(4^x\) exponentially decreases towards zero, thus shifting \(f(x)\) closely to \(y = -3\).
It's vital when graphing to acknowledge:
This occurs because as \(x\) tends towards negative infinity, \(4^x\) exponentially decreases towards zero, thus shifting \(f(x)\) closely to \(y = -3\).
It's vital when graphing to acknowledge:
- The graph will not fall below \(y = -3\), no matter how far left or how negative \(x\) becomes.
- This asymptote helps define the graph's boundary, guiding the shape and range of the exponential curve.