Chapter 4: Problem 23
Sketch the graph of \(f\) $$f(x)=3^{x}+3^{-x}$$
Short Answer
Expert verified
The graph of \( f(x) = 3^x + 3^{-x} \) is symmetric and has a local minimum at \( x=0 \).
Step by step solution
01
Identify the Function Type
The function given is \( f(x) = 3^x + 3^{-x} \). This is a combination of exponential functions because it involves terms of the form \( a^x \).
02
Analyze General Behavior
For large \( x \), the term \( 3^x \) dominates, making \( f(x) \) rise sharply. For large negative \( x \), the term \( 3^{-x} \) dominates, again making \( f(x) \) rise since \( 3^{-(-x)} = 3^x \).
03
Determine Symmetry
Since \( f(x) = 3^x + 3^{-x} \) is the sum of \( 3^x \) and its reciprocal \( 3^{-x} \), it is symmetric around the line \( x = 0 \). This makes it an even function: \( f(-x) = f(x) \).
04
Find Key Values and Behavior
Evaluate specific points such as \( f(0) = 3^0 + 3^0 = 2 \), \( f(1) = 3^1 + 3^{-1} = 3 + \frac{1}{3} = \frac{10}{3} \), and \( f(-1) = 3^{-1} + 3^1 = \frac{1}{3} + 3 = \frac{10}{3} \). Note that as \( x \to \pm \infty \), \( f(x) \to \infty \).
05
Calculate the Derivative for Critical Points
The derivative \( f'(x) = 3^x \ln(3) - 3^{-x} \ln(3) \). Setting the derivative to zero, \( 3^x \ln(3) = 3^{-x} \ln(3) \). This simplifies to \( 3^{2x} = 1 \), giving \( x = 0 \) as the only critical point.
06
Determine Local Behavior using Second Derivative
Calculate the second derivative: \( f''(x) = 3^x(\ln(3))^2 + 3^{-x}(\ln(3))^2 \). At \( x=0 \), \( f''(0) = 2(\ln(3))^2 > 0 \). This indicates a local minimum at \( x = 0 \) since the second derivative is positive.
07
Sketch the Graph
Start the sketch of the graph: plot the key points \( (0, 2) \), observe symmetry, draw two rising curves from \( x \to -\infty \) and \( x \to \infty \), with the lowest point at \( (0, 2) \). The graph should suggest an upward 'U' shape due to symmetry and behavior at extremes.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are mathematical functions of the form \( a^x \), where \( a \) is a constant base and \( x \) is the exponent. In the function \( f(x) = 3^x + 3^{-x} \), we have two exponential terms:
- \( 3^x \) - This increases rapidly as \( x \) becomes larger.
- \( 3^{-x} \) - This is the reciprocal of \( 3^x \) and decreases as \( x \) becomes larger, but increases as \( x \) becomes more negative.
Symmetry in Functions
Symmetry in functions refers to how a function's graph can be mirrored along a certain line. For the function \( f(x) = 3^x + 3^{-x} \), symmetry plays a crucial role. This function is symmetric around the y-axis, meaning it is unchanged if you substitute \( x \) with \( -x \).
- When \( f(-x) = f(x) \), the function is said to be symmetric around the y-axis, or sometimes referred to as even symmetry.
- This type of symmetry allows for practical graphing strategies since you only need to know how the graph behaves in either the positive or negative \( x \)-direction, and then mirror the result for the opposite side.
- Graphically, this means if you fold the graph along the y-axis, both halves will align perfectly.
Critical Points
Critical points are points on a graph where the derivative of the function is either zero or undefined, indicating potential maxima, minima, or saddle points. For \( f(x) = 3^x + 3^{-x} \), the derivative is given by:\[ f'(x) = 3^x \ln(3) - 3^{-x} \ln(3) \]To find critical points, we set \( f'(x) = 0 \):
- \( 3^x \ln(3) = 3^{-x} \ln(3) \) simplifies to \( 3^{2x} = 1 \).
- Solving yields \( 3^{2x} = 1 \) or \( x = 0 \).
Even Function
A function is classified as even if \( f(-x) = f(x) \) for all \( x \) in its domain. The function \( f(x) = 3^x + 3^{-x} \) meets this criterion:
- Substitute \( -x \) into the function: \( f(-x) = 3^{-x} + 3^{x} \).
- Since addition is commutative: \( 3^x + 3^{-x} = 3^{-x} + 3^x \), thus proving \( f(-x) = f(x) \).
Derivative Analysis
Derivative analysis involves examining the rate of change of a function's output with respect to its input. For \( f(x) = 3^x + 3^{-x} \), the derivative \( f'(x) = 3^x \ln(3) - 3^{-x} \ln(3) \) is critical to understanding how the function's graph behaves:
- This derivative indicates where the function is increasing or decreasing.
- Setting \( f'(x) = 0 \) leads to finding critical points, which are essential for identifying local minima or maxima.
- Further, the second derivative \( f''(x) = 3^x(\ln(3))^2 + 3^{-x}(\ln(3))^2 \) helps determine the concavity of the function's graph.
- In this instance, \( f''(0) > 0 \) suggests that \( x = 0 \) is a point of local minimum—a conclusion drawn when the second derivative is positive.