/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Determine whether the function \... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine whether the function \(f\) is one-to-one. $$f(x)=|x|$$

Short Answer

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The function \( f(x) = |x| \) is not one-to-one.

Step by step solution

01

Understand the Definition of a One-to-One Function

A function is defined as one-to-one (or injective) if and only if different inputs in the domain produce different outputs in the range. Mathematically, a function \( f \) is one-to-one if \( f(a) = f(b) \) implies that \( a = b \) for all \( a, b \) in the domain of \( f \).
02

Determine the Range of the Absolute Value Function

Consider the function \( f(x) = |x| \). The absolute value function takes any real number input and returns its non-negative magnitude. Hence, the range of \( f(x) = |x| \) is \([0, \infty)\).
03

Test Different Values in Its Domain

Select different values from the domain and evaluate them through the function. For example, if \( x = 3 \), then \( f(3) = |3| = 3 \). If \( x = -3 \), then \( f(-3) = |-3| = 3 \). Here, two different inputs, 3 and -3, give the same output, 3.
04

Apply the One-to-One Definition

Since \( f(3) = f(-3) \) but \( 3 eq -3 \), \( f(x) = |x| \) does not satisfy the condition for being a one-to-one function, which requires \( f(a) = f(b) \) to imply \( a = b \). Therefore, \( f \) is not injective.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Injectivity
When we talk about function injectivity, we're exploring the nature of a function where each output is uniquely mapped back to one specific input. In simpler terms, a function is injective — or one-to-one — if every single input in its domain turns into a unique output.
This special property means that no two different inputs should give us the same output. Mathematically, for a function \( f \) to be injective, if \( f(a) = f(b) \), then it must imply \( a = b \).
In the example of the absolute value function \( f(x) = |x| \), the function is not injective because different inputs, like 3 and -3, both give the same output, 3. This contradiction tells us that the function fails the injectivity test.
Understanding function injectivity is crucial when assessing how functions behave and ensuring no repetition in the mapping from inputs to outputs.
Absolute Value Function
The absolute value function is an important concept that arises in mathematics frequently. It takes every real number and essentially turns it positive. Written as \( f(x) = |x| \), regardless of whether \( x \) is negative or positive, \( f(x) \) always yields a non-negative output.
For instance, both positive 3 and negative 3 would map to the same absolute value, 3. The nature of this function makes it handy in situations where we are more interested in the magnitude rather than the sign of a number.
This behavior of the absolute value function, while practical, means that it cannot be injective, as noted before. Different numbers, 3 and -3 for example, will result in the same output under this function. This inherent symmetry is both a feature and a limitation when considering injectivity.
To master the absolute value function, practice converting various inputs and examining how they all become non-negative.
Function Range
Understanding the range of a function is crucial, as it tells us all the possible outputs we might get. For the absolute value function \( f(x) = |x| \), the range consists of all non-negative numbers.
Formally, this means that every output \( y \) satisfies \( y \geq 0 \), and can be represented as the interval \([0, \infty)\). However, it's important to remember that while the range could include most non-negative values, the nature of the transformation limits the function's injectivity.
The way the absolute value runs through its domain turns any negative or positive number to its distance from zero, leading to outputs confined to non-negativity. Thus, when evaluating functions like this, always consider how the domain is mapped onto the range — understanding both gives us a complete picture of the function's behavior.
Familiarity with these concepts enriches our appreciation of how outputs are generated and what values are reachable within that context.

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Most popular questions from this chapter

The functions \(f\) and \(g\) can be used to approximate \(e^{x}\) on the interval \([0,1] .\) Graph \(f, g,\) and \(y=e^{x}\) on the same coordinate plane, and compare the accuracy of \(f(x)\) and \(g(x)\) as an approximation to \(e^{x}\). $$f(x)=\frac{1}{2} x^{2}+x+1 ; \quad g(x)=0.84 x^{2}+0.878 x+1$$

Dissolving salt in water If 10 grams of salt is added to a quantity of water, then the amount \(q(t)\) that is undissolved after \(t\) minutes is given by \(q(t)=10\left(\frac{4}{5}\right)^{t}\). Sketch a graph that shows the value \(q(t)\) at any time from \(t=0\) to \(t=10\)

Approximate \(x\) to three significant figures. (a) \(\log x=3.6274\) (b) \(\log x=0.9469\) (c) \(\log x=-1.6253\) (d) \(\ln x=2.3\) (e) \(\ln x=0.05\) (f) \(\ln x=-1.6\)

Ozone layer One method of estimating the thickness of the ozone layer is to use the formula $$ \ln I_{0}-\ln I=k x $$ where \(I_{0}\) is the intensity of a particular wavelength of light from the sun before it reaches the atmosphere, \(I\) is the intensity of the same wavelength after passing through a layer of ozone \(x\) centimeters thick, and \(k\) is the absorption constant of ozone for that wavelength. Suppose for a wavelength of \(3176 \times 10^{-8} \mathrm{cm}\) with \(k=0.39, I_{0} / I\) is measured as \(1.12 .\) Approximate the thickness of the ozone layer to the nearest 0.01 centimeter.

Graph \(f\) and \(g\) on the same coordinate plane, and estimate the solution of the equation \(f(x)=g(x)\) $$f(x)=x ; \quad g(x)=-x^{2}-\log _{5} x$$

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