Chapter 2: Problem 83
Algebraic methods were used to find solutions to each of the following equations. Now solve the equation graphically by assigning the expression on the left side to \(Y_{1}\) and the number on the right side to \(\mathbf{Y}_{2}\) and then finding the \(x\) -coordinates of all points of intersection of the two graphs. (a) \(x^{5 / 3}=32\) (b) \(x^{4 / 3}=16\) (c) \(x^{2 / 3}=-36\) (d) \(x^{144}=125\) (e) \(x^{1 / 2}=-27\)
Short Answer
Step by step solution
Define Equation Graphs
Analyze Graphs for Intersections
Identify Points of Intersection
Validate Intersections
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Algebraic Methods
- For equation (a) \(x^{5/3} = 32\), the algebraic method involves raising both sides to a power that cancels out the exponent: \((x^{5/3})^{3/5} = 32^{3/5}\), yielding \(x = 4\).
- Similarly, for equation (b) \(x^{4/3} = 16\), raising both sides to the \(3/4\) power gives \(x = 8\).
Coordinate Plane
For solving equations graphically, we plot functions representing the two sides of an equation on this plane. For instance, with \(Y_1\) and \(Y_2\) defined in our exercise:
- Function \(Y_1 = x^{5/3}\) represents a curve that shows how the value of \(Y_1\) changes as \(x\) changes.
- Function \(Y_2 = 32\) is a horizontal line because it's independent of \(x\) and remains constant.
Exponentiation
- Fractional exponents represent roots; for example, \(x^{1/2}\) is the square root of \(x\), while \(x^{3/5}\) means the fifth root of \(x^3\).
- Negative exponents imply the reciprocal, for instance, \(x^{-n} = \frac{1}{x^n}\).
Function Intersection
In our exercise:
- Each equation creates a pair of functions: for example, \(Y_1 = x^{4/3}\) and \(Y_2 = 16\).
- The intersection point's \(x\)-coordinate is the solution to the equation \(x^{4/3} = 16\), confirming \(x = 8\).