Chapter 2: Problem 70
Estimate the solutions of the inequality. $$|0.3 x|-2>2.2-0.63 x^{2}$$
Short Answer
Expert verified
The solutions are \(x < -2.35\) or \(x > 2.35\).
Step by step solution
01
Expression Setup
The given inequality is \(|0.3x| - 2 > 2.2 - 0.63x^2\). We will work with each side separately to simplify the comparison.
02
Rearrange the Inequality
Bring all terms to one side of the inequality to facilitate comparison: \(|0.3x| - 2 - 2.2 + 0.63x^2 > 0\). Simplify it to \(|0.3x| + 0.63x^2 - 4.2 > 0\).
03
Analyze Absolute Value
Consider the two cases for the absolute value: Case 1 is when \(x \geq 0\) leading to \(0.3x\). Case 2 is when \(x < 0\) leading to \(-0.3x\).
04
Solve Case 1 (\(x \geq 0\))
Substitute \(0.3x\) for \(|0.3x|\) in \(0.3x + 0.63x^2 - 4.2 > 0\). Rearrange to \(0.63x^2 + 0.3x - 4.2 > 0\) and solve the quadratic equation \(0.63x^2 + 0.3x - 4.2 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) with \(a = 0.63\), \(b = 0.3\), \(c = -4.2\).
05
Quadratic Formula Application for Case 1
Calculate the discriminant: \(b^2 - 4ac = 0.3^2 - 4(0.63)(-4.2) = 0.09 + 10.584 = 10.674\). Find roots: \(x = \frac{-0.3 \pm \sqrt{10.674}}{1.26}\). Calculate \(x_1 = \frac{-0.3 + 3.267}{1.26}\) and \(x_2 = \frac{-0.3 - 3.267}{1.26}\). Evaluate to get approximate roots \(x_1 \approx 2.35\) and \(x_2 \approx -2.83\). Since \(x \geq 0\), consider \(x_1\) only.
06
Solve Case 2 (\(x < 0\))
Substitute \(-0.3x\) for \(|0.3x|\) in \(-0.3x + 0.63x^2 - 4.2 > 0\). Rearrange to \(0.63x^2 - 0.3x - 4.2 > 0\) and solve the quadratic equation \(0.63x^2 - 0.3x - 4.2 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\) where \(a=0.63\), \(b=-0.3\), \(c=-4.2\).
07
Quadratic Formula Application for Case 2
Calculate the discriminant: \(b^2 - 4ac = (-0.3)^2 - 4(0.63)(-4.2) = 0.09 + 10.584 = 10.674\). Find roots: \(x = \frac{-(-0.3) \pm \sqrt{10.674}}{1.26}\). Calculate \(x_1 = \frac{0.3 + 3.267}{1.26}\) and \(x_2 = \frac{0.3 - 3.267}{1.26}\). Evaluate to get approximate roots \(x_1 \approx 2.83\) and \(x_2 \approx -2.35\). Since \(x < 0\), consider \(x_2\) only.
08
Combine Solutions
Now combine the findings from both cases: \(x > 2.35\) and \(x < -2.35\). The solution is \(x < -2.35\) or \(x > 2.35\), which are the intervals where the inequality holds true.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
In mathematics, the quadratic formula is a crucial tool designed to solve quadratic equations. Let’s break it down to enhance understanding.A quadratic equation typically has the standard form of: \[ ax^2 + bx + c = 0 \]where \(a\), \(b\), and \(c\) are constants with \(a eq 0\). The quadratic formula allows you to find the solutions to this equation and is expressed as:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula works by completing the square of the quadratic expression. Here's a quick guide on how it is applied:
- Start by identifying the coefficients \(a\), \(b\), and \(c\) from your quadratic equation.
- Calculate the discriminant \(b^2 - 4ac\). This step is very important as it determines the nature of the roots.
- If the discriminant is positive, the equation has two distinct real roots. If it's zero, there is exactly one real root. A negative discriminant indicates the roots are complex.
- Substitute the values of \(a\), \(b\), and the discriminant into the formula to find the values of \(x\).
Absolute Value
The concept of absolute value focuses on the distance of a number from zero on the number line. Absolute value is denoted using vertical bars, such as \(|a|\), and it is always non-negative.The mathematical definition of absolute value is:
- If \(a\) is a positive number, then \(|a| = a\).
- If \(a\) is negative, then \(|a| = -a\).
Polynomial Inequality
The goal of solving a polynomial inequality is to find intervals on the real number line where the inequality is true. In our case, the inequality contained both a quadratic expression and an absolute value.Here’s how polynomial inequalities are generally approached:
- Rearrange all terms so that the polynomial is greater than, less than, or not equal to zero.
- Identify potential roots by solving equations derived from the inequality.
- Consider the number line. Use test points between these roots to determine where the polynomial satisfies the inequality. This helps define the intervals of interest.