/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Simplify the difference quotient... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify the difference quotient \(\frac{f(x+h)-f(x)}{h}\) if \(h \neq 0\). $$f(x)=1 / x^{2}$$

Short Answer

Expert verified
\(\frac{-2x - h}{(x+h)^2 x^2}\) is the simplified form of the difference quotient.

Step by step solution

01

Identify and Setup the Difference Quotient

First, recognize the function given: \( f(x) = \frac{1}{x^2} \). The difference quotient is \( \frac{f(x+h) - f(x)}{h} \). Start by finding \( f(x+h) \).
02

Calculate \( f(x+h) \)

To find \( f(x+h) \), substitute \( x+h \) into \( f(x) \): \[ f(x+h) = \frac{1}{(x+h)^2} \]
03

Substitute into the Difference Quotient

Substitute \( f(x+h) \) and \( f(x) \) into the difference quotient:\[ \frac{f(x+h) - f(x)}{h} = \frac{\frac{1}{(x+h)^2} - \frac{1}{x^2}}{h} \]
04

Find a Common Denominator

The goal is to subtract the two fractions \( \frac{1}{(x+h)^2} \) and \( \frac{1}{x^2} \). The common denominator is \( (x+h)^2 x^2 \), so rewrite each fraction:\[ \frac{x^2}{(x+h)^2 x^2} - \frac{(x+h)^2}{(x+h)^2 x^2} \]
05

Simplify the Numerator

Combine the fractions over the common denominator:\[ \frac{x^2 - (x+h)^2}{(x+h)^2 x^2} \]Simplify the numerator \( x^2 - (x^2 + 2xh + h^2) = -2xh - h^2 \):\[ \frac{-2xh - h^2}{(x+h)^2 x^2} \]
06

Adjust the Fraction by \( h \) in the Denominator

Divide the numerator by the \( h \) in the denominator:\[ \frac{-2xh - h^2}{h} \frac{1}{(x+h)^2 x^2} = \frac{-2x - h}{(x+h)^2 x^2} \]
07

Conclusion

The simplified form of the difference quotient \( \frac{f(x+h) - f(x)}{h} \) when \( f(x) = \frac{1}{x^2} \) is:\[ \frac{-2x - h}{(x+h)^2 x^2} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Simplification
Function simplification is an essential process in calculus that helps in handling complex expressions by breaking them down into simpler forms that are easier to work with. In our exercise, the function in question is \(f(x) = \frac{1}{x^2}\). This function is initially presented as part of a difference quotient, \(\frac{f(x+h) - f(x)}{h}\), which might appear complex at the outset. However, by applying algebraic techniques, we can streamline the expression into a more manageable format.

Simplification often involves several common steps:
  • Identifying and combining like terms.
  • Reducing fractions by finding common denominators.
  • Canceling terms where possible to simplify the expression fully.
These steps are crucial for understanding the trajectory of functions, especially when preparing them for further processes like taking limits or derivatives.
Algebraic Fractions
Algebraic fractions involve fractions that have polynomials in their numerators, denominators, or both. In the context of the difference quotient, \(\frac{f(x+h) - f(x)}{h}\) transforms into a fraction where both the numerator and denominator may be polynomial expressions. For our function, \(\frac{1}{(x+h)^2}\) and \(\frac{1}{x^2}\) are subtracted as part of the calculation.

Handling these fractions efficiently requires finding a common denominator, a technique that allows us to combine and simplify these terms. To proceed:
  • Determine the least common denominator, which in our case is \((x+h)^2 x^2\).
  • Rewrite each fraction with this common denominator.
  • Subtract the numerators to obtain a single simplified fraction.
This process is key in transitioning from a messy format to a cleaned-up expression that lays the groundwork for taking limits or derivatives.
Limit Process
The limit process is a fundamental concept that underlies the calculus subject area, especially when dealing with difference quotients. By examining how a function behaves as a variable approaches a particular value, limits allow us to define smooth transitions between discrete points. In our context of the difference quotient, sending \(h\) to zero (\(h\to 0\)) enables us to find the rate of change at an exact point.

This process involves:
  • Carefully analyzing the expression within the limit context, particularly after thorough simplification.
  • Identifying terms that cancel out or vanish as \(h\) approaches zero.
  • Transforming the expression to focus on those terms remaining significant as the limit is applied.
Practicing this process leads us to understand instantaneous rates of change, which plays a pivotal role in multiple calculus applications.
Derivative Concept
The derivative concept is a core calculus idea that gives us insight into how functions change. It represents the function's rate of change or slope at any given point. In essence, the derivative tells us how a small change in \(x\) affects \(f(x)\).

In practical terms, the derivative of a function \(f(x)\) at a point is found using the difference quotient as \(h\to 0\). For our problem, once we simplify, the derivative can be observed from the expression \(\frac{-2x - h}{(x+h)^2 x^2}\). When \(h\) is forced to zero, we see the behavior stabilizing into \(-\frac{2x}{x^4}\), revealing the derivative for \(f(x)=\frac{1}{x^2}\) as \(-\frac{2}{x^3}\).

Understanding derivatives equips us to predict how any small change in the values of \(x\) could influence the outcome of the function \(f(x)\). This knowledge is pivotal, both in mathematics and in real-world change calculations.

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