/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find (a) \((f \circ g)(x)\) and ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find (a) \((f \circ g)(x)\) and the domain of \(f \circ g\) and (b) \((g \circ f)(x)\) and the domain of \(g \circ f\). $$f(x)=x^{2}-4, \quad g(x)=\sqrt{3 x}$$

Short Answer

Expert verified
(a) \((f \circ g)(x) = 3x - 4\), domain is \(x \geq 0\). (b) \((g \circ f)(x) = \sqrt{3x^2 - 12}\), domain is \((-\infty, -2] \cup [2, \infty)\).

Step by step solution

01

Find the Composite Function \((f \\circ g)(x)\)

To find \((f \circ g)(x)\), we need to substitute \(g(x)\) into \(f(x)\). This means replacing \(x\) in \(f(x) = x^2 - 4\) with \(g(x) = \sqrt{3x}\). So: \((f \circ g)(x) = f(g(x)) = (\sqrt{3x})^2 - 4 = 3x - 4\).
02

Determine the Domain of \((f \\circ g)(x)\)

The domain of \(g(x) = \sqrt{3x}\) is determined by the condition under the square root. We need \(3x \geq 0\), which implies \(x \geq 0\). Since \(f(x)\) is a polynomial, its domain is all real numbers, and therefore, the domain of \((f \circ g)(x)\) is the same as that of \(g\), that is, \(x \geq 0\).
03

Find the Composite Function \((g \\circ f)(x)\)

To find \((g \circ f)(x)\), substitute \(f(x)\) into \(g(x)\). Replace \(x\) in \(g(x) = \sqrt{3x}\) with \(f(x) = x^2 - 4\), so: \((g \circ f)(x) = g(f(x)) = \sqrt{3(x^2 - 4)} = \sqrt{3x^2 - 12}\).
04

Determine the Domain of \((g \\circ f)(x)\)

The expression \(\sqrt{3x^2 - 12}\) is defined when the quantity under the square root is non-negative. So, solve \(3x^2 - 12 \geq 0\). Simplify to \(x^2 \geq 4\), which gives \(x \geq 2\) or \(x \leq -2\). Thus, the domain of \((g \circ f)(x)\) is \((-\infty, -2] \cup [2, \infty)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
The domain of a function is crucial in understanding where a function can exist. It refers to all the possible input values (usually represented as 'x') for which the function is defined. For example, when dealing with the function \(g(x) = \sqrt{3x}\), the expression under the square root - known as the radicand - must be non-negative, as the square root of a negative number is not defined in the set of real numbers.
This means \(3x \geq 0\) must hold, leading to the solution \(x \geq 0\). Hence, the domain of \(g(x)\) is all non-negative numbers.
Being able to determine the domain ensures that you avoid applying the function to values where it doesn't work, such as negative inputs under a square root. Remember that polynomials like \(f(x) = x^2 - 4\) have domains encompassing all real numbers because they are continuous and defined everywhere on the number line.
Function Composition
Function composition is a way of chaining functions together, like connecting a series of machines where the output of one is the input of the next. When you compose functions \(f\) and \(g\) as \((f \circ g)(x)\), you are plugging the entire function \(g(x)\) into each 'x' of \(f(x)\).
This action creates a composite function, which can often help simplify complex relationships into single expressions.
For example, if \(f(x) = x^2 - 4\) and \(g(x) = \sqrt{3x}\), then \((f \circ g)(x) = f(g(x)) = (\sqrt{3x})^2 - 4 = 3x - 4\). Notice how \(g(x)\) is inserted wherever \(x\) appears in \(f(x)\).
This combined function has a domain that is influenced by both original functions, particularly \(g(x)\) because its output forms the input to \(f(x)\).
It’s important to verify that composing these functions aligns with their domains.
Polynomials
Polynomials are mathematical expressions involving a sum of powers of one or more variables multiplied by coefficients. They form the foundations of algebra and are often easy to handle because their domains are generally all real numbers.
A polynomial like \(f(x) = x^2 - 4\) is continuous, meaning it creates a smooth curve on a graph without breaks or holes. This is due to the very nature of polynomials being completely defined by basic arithmetic operations - addition, subtraction, multiplication, and non-negative integer exponents.
Key features, such as the highest power, help determine the degree of the polynomial, which in turn influences its behavior, such as the number of turning points.
  • The degree tells us about the potential complexity of the polynomial in terms of graph shape and roots.
  • In the expression \(x^2 - 4\), the highest power is 2, making it a quadratic polynomial with two roots.
Understanding these properties helps simplify potential complex relationships when working with equations that incorporate polynomials.
Square Roots
Square roots involve finding a number that, when multiplied by itself, gives the original number under the root. This operation is crucial in solving and analyzing many mathematical problems.
In context, look at the function \(g(x) = \sqrt{3x}\). Here, the square root operation is only valid when its input, or radicand, is non-negative because we typically deal with real numbers and the square root of negative numbers is imaginary.
This leads to some constraints on the domain, requiring \(3x \geq 0\) and thus \(x \geq 0\).
The square root function produces only non-negative results if the radicand is non-negative. This makes the comprehension of such operations crucial when determining domains and understanding the behavior of expressions such as \((g \circ f)(x) = \sqrt{3(x^2 - 4)}\).
Whenever dealing with square roots, ensuring the radicand doesn't fall into the negative realm is key to validating the function.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There are two car rental options available for a four-day trip. Option I is 45 dollar per day, with 200 free miles and 0.40 dollar per mile for each additional mile. Option II is 558.75 per day, with a charge of 0.25 dollar per mile. (a) Determine the cost of a 500 -mile trip for both options. (b) Model the data with a cost function for each four day option. (c) Make a table that lists the mileage and the charge for each option for trips between 100 and 1200 miles, using increments of 100 miles. (d) Use the table to determine the mileages at which each option is preferable.

Graph \(f\) in the viewing rectangle \([-12,12]\) by \([-8,8] .\) Use the graph of \(f\) to predict the graph of \(g .\) Verify your prediction by graphing \(g\) in the same viewing rectangle. $$f(x)=0.5 x^{3}-4 x-5 ; \quad g(x)=0.5 x^{3}-4 x-1$$

Sketch the graph of \(f\) $$f(x)=\left\\{\begin{array}{ll} 3 & \text { if } x \leq-1 \\ -2 & \text { if } x>-1 \end{array}\right.$$

The human camnonball In the 1940 s, the human cannonball stunt was performed regularly by Emmanuel Zacchini for The Ringling Brothers and Barnum \& Bailey Circus. The tip of the cannon rose 15 feet off the ground, and the total horizontal distance traveled was 175 feet. When the cannon is aimed at an angle of \(45^{\circ},\) an equation of the parabolic flight (see the figure) has the form \(y=a x^{2}+x+c\) (a) Use the given information to find an equation of the flight. (b) Find the maximum height attained by the human cannonball.

Spreading flire \(A\) fire has started in a dry open field and is spreading in the form of a circle. If the radius of this circle increases at the rate of \(6 \mathrm{ft} / \mathrm{min}\), express the total fire area \(A\) as a function of time \(t\) (in minutes).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.