/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 (a) Use the quadratic formula to... [FREE SOLUTION] | 91Ó°ÊÓ

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(a) Use the quadratic formula to find the zeros of \(f .\) (b) Find the maximum or minimum value of \(f(x)\) (c) Sketch the graph of \(f\) $$f(x)=x^{2}+4 x+9$$

Short Answer

Expert verified
No real zeros; Minimum value of 5 at \( x = -2 \).

Step by step solution

01

Identify the coefficients

The quadratic formula is used to find the zeros of a quadratic equation in the form \( ax^2 + bx + c = 0 \). For the function \( f(x) = x^2 + 4x + 9 \), identify the coefficients: \( a = 1 \), \( b = 4 \), and \( c = 9 \).
02

Set up the quadratic formula

The quadratic formula is given by \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute \( a = 1 \), \( b = 4 \), and \( c = 9 \) into the formula.
03

Calculate the discriminant

The discriminant \( \Delta \) is \( b^2 - 4ac \). Calculate it: \( (4)^2 - 4 \cdot 1 \cdot 9 = 16 - 36 = -20 \). Since the discriminant is negative, the quadratic equation has no real roots.
04

Discuss the nature of the zeros

Because the discriminant is negative, \( f(x) \) does not intersect the x-axis (no real zeros). The solutions are complex numbers: \( x = \frac{-4 \pm i\sqrt{20}}{2} \). We simplify to \( x = -2 \pm i\sqrt{5} \).
05

Find the vertex

The vertex of the parabola represented by \( f(x) = ax^2 + bx + c \) can be found at \( x = -\frac{b}{2a} \). Substitute \( b = 4 \) and \( a = 1 \) to get the x-coordinate of the vertex: \( x = -\frac{4}{2 \cdot 1} = -2 \).
06

Calculate the maximum or minimum value

Substitute \( x = -2 \) into the function to find the y-coordinate of the vertex: \( f(-2) = (-2)^2 + 4(-2) + 9 = 4 - 8 + 9 = 5 \). Thus, the minimum value of \( f(x) \) is 5.
07

Sketch the graph

The graph of \( f(x) = x^2 + 4x + 9 \) is an upward-opening parabola with its vertex at (-2, 5). The parabola will not intersect the x-axis because there are no real zeros. The y-intercept is \( (0, 9) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
The quadratic formula is a fundamental tool in algebra used to solve quadratic equations, which are equations in the form \( ax^2 + bx + c = 0 \). This formula provides a method to find the values of \( x \) that satisfy the equation.
A standard quadratic equation is represented as:
  • \( ax^2 + bx + c = 0 \)
Here, \( a \), \( b \), and \( c \) are known as the coefficients.
The quadratic formula is given by:
  • \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
This powerful equation allows us to find the roots of any quadratic equation reliably, simplifying the process of solving problems related to parabolas. The components under the square root in the formula have a special significance, which leads us to our next concept: the discriminant.
Discriminant
The discriminant is an essential part of the quadratic formula and plays a vital role in determining the nature of the roots of a quadratic equation.
It is represented by the expression \( b^2 - 4ac \). The value of the discriminant gives us information about the type of roots the quadratic equation has:
  • If \( b^2 - 4ac > 0 \), the quadratic has two distinct real roots.
  • If \( b^2 - 4ac = 0 \), the quadratic has exactly one real root, which is also known as a repeated root.
  • If \( b^2 - 4ac < 0 \), the quadratic has no real roots and instead has two complex roots.
In the example \( f(x) = x^2 + 4x + 9 \), the discriminant is \( -20 \), indicating that the equation has complex roots, leading us to explore these complex solutions further.
Complex Roots
Complex roots occur when the discriminant \( b^2 - 4ac \) is negative. In this scenario, the quadratic equation has solutions that involve imaginary numbers.
Imaginary numbers are based around \( i \), the square root of -1. When presented with complex roots, the solutions are usually expressed as \( x = a \pm bi \), where \( a \) and \( b \) are real numbers.
For the function \( f(x) = x^2 + 4x + 9 \), the complex roots are calculated as follows:
The discriminant \( -20 \) leads to a square root of \( 20 \) multiplied by \( i \).
Thus, the roots are \( x = -2 \pm i\sqrt{5} \). These complex solutions indicate that the graph of \( f(x) \) does not cross the x-axis.
The understanding of complex roots is crucial for fully grasping solutions beyond the real number system.
Vertex of a Parabola
The vertex of a parabola is a key feature as it represents the turning point, which could either be a maximum or a minimum point on the graph.
For a standard quadratic function \( f(x) = ax^2 + bx + c \), the x-coordinate of the vertex can be found using the formula:
  • \( x = -\frac{b}{2a} \)
Once the x-coordinate is known, substituting it back into the original quadratic equation helps us find the corresponding y-coordinate.
In the example \( f(x) = x^2 + 4x + 9 \), the vertex is calculated as follows:
  • x-coordinate: \( x = -\frac{4}{2 \times 1} = -2 \)
  • y-coordinate: \( f(-2) = (-2)^2 + 4(-2) + 9 = 5 \)
Thus, the vertex is at \((-2, 5)\). This point is the minimum value on the graph since the parabola opens upwards.
Understanding the vertex helps in sketching the graph of a parabola and analyzing its features.

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