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Exer. \(1-20\) : Sketch the graph of the equation, and label the \(x\) - and \(y\) -intercepts. $$y=-x^{3}+1$$

Short Answer

Expert verified
The graph is a downward-sloping cubic curve with x-intercept (1, 0) and y-intercept (0, 1).

Step by step solution

01

Identify the Equation Type

The given equation is \( y = -x^3 + 1 \), which is a cubic function. Cubic functions generally have an S-shaped curve.
02

Find the Y-Intercept

To find the y-intercept, set \( x = 0 \) in the equation. This gives \( y = -(0)^3 + 1 = 1 \). Therefore, the y-intercept is at the point \( (0, 1) \).
03

Find the X-Intercepts

To find x-intercepts, set \( y = 0 \) in the equation: \( 0 = -x^3 + 1 \). Solving for \( x \) gives \( x^3 = 1 \), so \( x = 1 \). Thus, the x-intercept is at the point \( (1, 0) \).
04

Analyze the End Behavior

Since the leading term is \( -x^3 \), as \( x \rightarrow fty \), \( y \rightarrow -fty \), and as \( x \rightarrow -fty \), \( y \rightarrow fty \). This indicates the graph falls to the right and rises to the left.
05

Sketch the Graph

Plot the intercepts: the y-intercept \( (0, 1) \) and the x-intercept \( (1, 0) \). Use the end behavior from Step 4 to draw the curve passing through these points. The graph should start in the third quadrant, pass through the y-intercept, cross the x-axis at \( x=1 \), and end in the fourth quadrant.
06

Verify the Curve Trend

To confirm the shape, check a few more points. For example, for \( x = -1 \), \( y = -(-1)^3 + 1 = 2 \). For \( x = 2 \), \( y = -(2)^3 + 1 = -7 \). Plot these points to verify the correctness of the curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Techniques
Graphing a cubic function can initially seem challenging, but breaking it down into simple steps makes it manageable. Start by identifying the important characteristics of the function, such as its shape and key points to plot on the graph. Cubic functions typically have an S-shaped curve, with one or zero turning points.
When you plot a function like our given equation \( y = -x^3 + 1 \), take note of the different regions in the graph that you need to sketch. The graph of this function will curve since it’s a degree three polynomial, and its turning points create an S-curve. Make sure to carefully plot the x- and y-intercepts as starting anchors.
  • Plot the Intercepts: Determine and plot the y-intercept where the curve crosses the y-axis and the x-intercept(s) where it crosses the x-axis.
  • Analyze End Behavior: Understand how the graph behaves as \( x \) tends towards infinity and negative infinity.
  • Sketch the Curve: Use the intercepts and end behavior to draft the initial shape of the graph. Validate its appearance by checking additional points.
This step-by-step approach not only makes it easier to graph but also allows you to visualize how the function behaves in a broader sense.
Intercepts
Intercepts are key points through which the graph of a function passes, intersecting the axes. They are simple to find and crucial for sketching any function accurately. Let's delve into how you find them for our cubic function.

To find the **y-intercept**, set \( x = 0 \) and solve for \( y \). This method works because the y-intercept is the point where the graph crosses the y-axis, meaning \( x \) is 0 at that point. For the equation \( y = -x^3 + 1 \), substituting \( x = 0 \) gives \( y = 1 \). Therefore, the y-intercept is at \( (0, 1) \).

Finding the **x-intercepts** is a slightly different process. Here, set \( y = 0 \) and solve for \( x \). This identifies where the graph crosses the x-axis, where \( y \) is zero. Solving \( 0 = -x^3 + 1 \) results in \( x = 1 \), which gives us an x-intercept at \( (1, 0) \). These intercepts offer a simple way to anchor your graph, giving you points to plot and start constructing the curve.
End Behavior Analysis
Understanding how a graph stretches out towards infinity in either direction is known as its end behavior. This is especially important for cubic functions like \( y = -x^3 + 1 \), as it determines how the graph rises and falls.

With our cubic function, focus on the leading term, \( -x^3 \), to predict the end behavior. This term dominates as \( x \) becomes very large (positively or negatively). Notice that:
  • As \( x \) goes to infinity \((+fty)\), \( y \) tends towards negative infinity \((-fty)\). This means the graph falls to the right.
  • As \( x \) goes to negative infinity \((-fty)\), \( y \) increases towards infinity \((+fty)\). This means the graph rises to the left.
These observations about the end behavior help create the general shape of the cubic function, confirming its S-curve nature. Evaluating the end behavior lets us know where our graph starts and ends as we trace it out, ensuring accuracy when sketching the cubic function.

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