Chapter 2: Problem 13
(a) Use the quadratic formula to find the zeros of \(f .\) (b) Find the maximum or minimum value of \(f(x)\) (c) Sketch the graph of \(f\) $$f(x)=x^{2}-4 x$$
Short Answer
Expert verified
The zeros are 0 and 4; the minimum value is -4.
Step by step solution
01
Identify the coefficients for the quadratic formula
The quadratic function is given by \( f(x) = x^2 - 4x \). Identify the coefficients: \(a = 1\), \(b = -4\), and \(c = 0\).
02
Use the quadratic formula to find the zeros
The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). Substitute the values of \(a\), \(b\), and \(c\): \(x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 1 \cdot 0}}{2 \cdot 1}\). Simplifying, we get \(x = \frac{4 \pm \, 4}{2}\). So, \(x = 0\) or \(x = 4\).
03
Determine the vertex to find the maximum or minimum value
For a quadratic in the form \(ax^2 + bx + c\), the vertex \(x\)-coordinate is given by \(x = -\frac{b}{2a}\). Substitute \(b = -4\) and \(a = 1\) to find \(x = -\frac{-4}{2 \cdot 1} = 2\).
04
Calculate the function value at the vertex
Substitute \(x = 2\) into the function to find the maximum or minimum value: \(f(2) = 2^2 - 4 \cdot 2 = 4 - 8 = -4\). This indicates the minimum value of the function is \(-4\).
05
Sketch the graph of the quadratic function
The graph of the function \(f(x) = x^2 - 4x\) is a parabola opening upwards since \(a > 0\). It passes through the zeros \(x = 0\) and \(x = 4\) and has a vertex at the point \((2, -4)\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Zeros of a Function
Finding the zeros of a function is a crucial aspect of understanding quadratic equations. These zeros are also known as the roots or x-intercepts of the function. For the quadratic function given by \( f(x) = x^2 - 4x \), the zeros are the values of \( x \) for which \( f(x) = 0 \).
To find these zeros, we can use the quadratic formula, which is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). By substituting the coefficients \( a = 1 \), \( b = -4 \), and \( c = 0 \), we can calculate:
\[ x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 1 \cdot 0}}{2 \cdot 1} = \frac{4 \pm 4}{2} \]
This simplifies to \( x = 0 \) and \( x = 4 \). These values indicate where the function touches or crosses the x-axis (i.e., the zeros).
To find these zeros, we can use the quadratic formula, which is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). By substituting the coefficients \( a = 1 \), \( b = -4 \), and \( c = 0 \), we can calculate:
\[ x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 1 \cdot 0}}{2 \cdot 1} = \frac{4 \pm 4}{2} \]
This simplifies to \( x = 0 \) and \( x = 4 \). These values indicate where the function touches or crosses the x-axis (i.e., the zeros).
- The zeros represent the solutions to the equation \( x^2 - 4x = 0 \).
- They signify points where the graph intersects the x-axis.
- Having multiple zeros may mean the function touches the axis at different points.
Vertex of a Parabola
In a quadratic function, the vertex of a parabola is the peak or the lowest point of the curve. It represents either a maximum or a minimum value of the function, depending on whether the parabola opens upwards or downwards. For the function \( f(x) = x^2 - 4x \), since \( a = 1 \), the parabola opens upwards, indicating that the vertex is a minimum point.
- The vertex \(x\)-coordinate is determined using \( x = -\frac{b}{2a} \), where \( b = -4 \) and \( a = 1 \).
- This calculates to \( x = -\frac{-4}{2 \cdot 1} = 2 \).
- Plug \( x = 2 \) back into the function to find the function value: \( f(2) = 2^2 - 4 \cdot 2 = -4 \).
Quadratic Formula
The quadratic formula is a powerful solution tool for finding the roots of any quadratic equation, given in the standard form \( ax^2 + bx + c = 0 \). This elegant formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), provides the x-values where the function intersects the x-axis, solving the equation directly.
- The expression under the square root, \( b^2 - 4ac \), is known as the discriminant. It determines the nature of the solutions:
- If it is positive, the function has two distinct real roots.
- If zero, the function has one real repeated root.
- If negative, the roots are complex (non-real).
- In the exercise \( f(x) = x^2 - 4x \), substituting the coefficients \( a = 1 \), \( b = -4 \), and \( c = 0 \) into the formula provided real-valued roots: \( x = 0 \) and \( x = 4 \).