Chapter 2: Problem 1
Exer. \(1-20\) : Sketch the graph of the equation, and label the \(x\) - and \(y\) -intercepts. $$y=2 x-3$$
Short Answer
Expert verified
Y-intercept: (0, -3), X-intercept: \(\left(\frac{3}{2}, 0\right)\)
Step by step solution
01
Identify the Equation Form
The given equation is in the slope-intercept form, \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Here, \(y = 2x - 3\), so the slope \(m = 2\), and the y-intercept \(b = -3\).
02
Find the Y-Intercept
The y-intercept is the point where the graph crosses the y-axis. In the equation \(y = 2x - 3\), the y-intercept is given directly as \(b = -3\). Therefore, the y-intercept is the point \((0, -3)\).
03
Find the X-Intercept
The x-intercept is the point where the graph crosses the x-axis (where \(y = 0\)). To find it, set \(y = 0\) in the equation \(y = 2x - 3\) and solve for \(x\): \(0 = 2x - 3\). Add 3 to both sides to get \(2x = 3\), then divide by 2 to get \(x = \frac{3}{2}\). So, the x-intercept is \(\left(\frac{3}{2}, 0\right)\).
04
Plot the Intercepts
Plot the points \((0, -3)\) and \(\left(\frac{3}{2}, 0\right)\) on a graph. These points represent the y-intercept and x-intercept, respectively.
05
Draw the Line
Using the plotted intercepts, draw a straight line that passes through both points. Since it's a straight line, it will continue infinitely in both directions. Label the intercepts on the graph: \((0, -3)\) on the y-axis, and \(\left(\frac{3}{2}, 0\right)\) on the x-axis.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Linear Equations
When you graph a linear equation like this one, you're essentially drawing the path of that equation on a coordinate plane. Linear equations are equations of the first degree, which means they create straight lines when graphed. A useful starting point is knowing that linear equations in the form of \( y = mx + b \) are in what’s called the slope-intercept form. This form makes it easy for us to identify two key aspects needed to graph the line: the slope \( m \) and the y-intercept \( b \).
\[\]
\[\]
- The slope \( m \) determines the tilt or steepness of the line. In our case, with \( y = 2x - 3 \), the slope is 2, which means for every step you move to the right (along the x-axis), the line steps up 2 units on the y-axis.
- The y-intercept \( b \) represents where the line crosses the y-axis. Here, it's \( -3 \), meaning the line meets the y-axis at the point (0, -3).
Finding Intercepts
Finding intercepts is crucial as they guide us in drawing the line that represents our linear equation. One intercept tells you where the line crosses the x-axis, at what x value y touches zero, called the x-intercept. The other, the y-intercept, shows where the line crosses the y-axis, at what y value when x is zero.
\[\]To find the y-intercept, you simply look at the equation in its slope-intercept form \( y = mx + b \). Here, \( b \) is the y-intercept. Thus, for \( y = 2x - 3 \), the y-intercept is \( -3 \). The point on the graph is (0, -3).
\[\]Calculating the x-intercept involves setting y to zero and solving for x. For example, in the equation \( y = 2x - 3 \), setting \( y = 0 \) gives 0 = 2x - 3. Solving this, you add 3 to both sides yielding 2x = 3, and dividing by 2 results in \( x = \frac{3}{2} \). This gives an intercept at the point \( \left ( \frac{3}{2}, 0 \right ) \). By plotting these intercepts, you can easily visualize your linear equation.
\[\]To find the y-intercept, you simply look at the equation in its slope-intercept form \( y = mx + b \). Here, \( b \) is the y-intercept. Thus, for \( y = 2x - 3 \), the y-intercept is \( -3 \). The point on the graph is (0, -3).
\[\]Calculating the x-intercept involves setting y to zero and solving for x. For example, in the equation \( y = 2x - 3 \), setting \( y = 0 \) gives 0 = 2x - 3. Solving this, you add 3 to both sides yielding 2x = 3, and dividing by 2 results in \( x = \frac{3}{2} \). This gives an intercept at the point \( \left ( \frac{3}{2}, 0 \right ) \). By plotting these intercepts, you can easily visualize your linear equation.
Solving for X and Y
Being able to solve for x and y in linear equations is a handy skill that helps to break down what a line represents on a graph. In our current equation \( y = 2x - 3 \), solving for y is straightforward because the equation is already in the format of \(y = mx + b\). This format gives y directly based on any value chosen for x.
\[\]If you wanted to find a specific y for a chosen x, you substitute x into the equation. For example, if x equals 1, you plug it in as follows: \( y = 2(1) - 3 \), solving gives \( y = -1 \).
\[\]Sometimes you might need to do the reverse and solve for x given a specific y value. This reversal is common when finding the x-intercept. For instance, to find when y equals zero, you rearrange the equation:
\[\]If you wanted to find a specific y for a chosen x, you substitute x into the equation. For example, if x equals 1, you plug it in as follows: \( y = 2(1) - 3 \), solving gives \( y = -1 \).
\[\]Sometimes you might need to do the reverse and solve for x given a specific y value. This reversal is common when finding the x-intercept. For instance, to find when y equals zero, you rearrange the equation:
- Start with the equation, 0 = 2x - 3.
- Add 3 to both sides to isolate the term with x, giving 2x = 3.
- Lastly, solve for x by dividing both sides by 2, yielding \( x = \frac{3}{2} \).