Chapter 10: Problem 6
Find the eccentricity, and classify the conle. Sketch the graph, and label the vertices. $$r=\frac{3}{2-2 \sin \theta}$$
Short Answer
Expert verified
The conic is a parabola with eccentricity 1. Vertex at \((\frac{3}{2}, 0)\).
Step by step solution
01
Identify the General Form
The given polar equation is \( r = \frac{3}{2 - 2 \sin \theta} \). This is of the form \( r = \frac{ed}{1 - e \sin \theta} \), which matches the equation for a conic section with a focus at the pole. Here, \(ed = 3\) suggests a relationship for identifying \(e\).
02
Extract the Eccentricity
To find the eccentricity \(e\), compare the given polar equation with \( r = \frac{ed}{1 - e \sin \theta} \). Here, \(e = 2\) as it is the coefficient of \(\sin \theta\), and \( d = \frac{3}{2} \). Hence, the eccentricity \(e\) is 1.
03
Classify the Conic
The conic is classified based on the value of \(e\). Since \(e = 1\), this indicates that the conic section is a parabola.
04
Verify the Conic Type
The condition \(e = 1\) in polar equations reflects that the conic is a parabola because parabolas have exactly one eccentricity value that is equal to 1.
05
Sketch the Graph and Identify Vertices
A parabola with a polar form \(r = \frac{3}{2 - 2 \sin \theta}\) is symmetric with respect to the vertical axis when the sine function is involved. To find the vertex, set \(\theta = 0\) to calculate \(r = \frac{3}{2}\). Hence, the vertex is at \((\frac{3}{2}, 0)\) in polar coordinates.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Equations
Polar equations are a way to represent curves using a coordinate system based on radius (\(r\)) and angle (\(\theta\)). This is different from the Cartesian system where you use \(x\) and \(y\) coordinates. In polar coordinates:
By comparing this equation with the general form \(r = \frac{ed}{1 - e \sin \theta}\), we can identify the type of conic section. The important parameter here is the eccentricity (\(e\)), which determines the conic's shape.
- The origin is called the pole.
- The horizontal axis from the pole is the polar axis.
By comparing this equation with the general form \(r = \frac{ed}{1 - e \sin \theta}\), we can identify the type of conic section. The important parameter here is the eccentricity (\(e\)), which determines the conic's shape.
Conic Sections
Conic sections are curves obtained by intersecting a plane with a cone. The shape of the conic depends on the angle and position of the intersection. There are several types of conic sections:
- Circle: Occurs when the plane cuts the cone parallel to the base.
- Ellipse: Formed when the plane cuts through the cone at an angle, but not steep enough to be parallel.
- Parabola: Result from the plane being parallel to a cone's side.
- Hyperbola: Created when the plane cuts through both nappes of the cone.
- Eccentricity = 0: Circle
- 0 < Eccentricity < 1: Ellipse
- Eccentricity = 1: Parabola
- Eccentricity > 1: Hyperbola
Parabola
A parabola is a special conic section characterized by being symmetric and having an eccentricity (\(e\)) of exactly 1. It is defined as the set of all points that are equidistant from a fixed point called the "focus" and a line called the "directrix".
In polar coordinates, the parabola will typically have the equation form \(r = \frac{ed}{1 - e \sin \theta}\). This becomes a parabola when the factor \(e\) equals 1. Let's consider the equation \(r = \frac{3}{2 - 2 \sin \theta}\).This matches the general parabola form since:
In polar coordinates, the parabola will typically have the equation form \(r = \frac{ed}{1 - e \sin \theta}\). This becomes a parabola when the factor \(e\) equals 1. Let's consider the equation \(r = \frac{3}{2 - 2 \sin \theta}\).This matches the general parabola form since:
- The coefficient of \(\sin \theta\) is 2, equating to our \(e = 1\).
- The form is confirmed by the comparison with \(1 - e \sin \theta\).