Chapter 10: Problem 27
Find an equation for the ellipse that has its center at the origin and satisfies the given conditions. \(x\) -intercepts \(\pm 2\) \(\quad\) \(y\) -intercepts \(\pm \frac{1}{3}\)
Short Answer
Expert verified
The equation of the ellipse is \( \frac{x^2}{4} + 9y^2 = 1 \).
Step by step solution
01
Understand the Problem
We need to find the equation of an ellipse centered at the origin with specific intercepts. The conditions are: x-intercepts at \( \pm 2 \) and y-intercepts at \( \pm \frac{1}{3} \). These intercepts will help us determine \( a \) and \( b \), the lengths of the semi-major and semi-minor axes.
02
Identify the Structure of the Ellipse Equation
The standard form of the equation of an ellipse centered at the origin is \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). Where \( a \) is the length of the semi-major axis and \( b \) is the length of the semi-minor axis.
03
Determine the Values of \( a \) and \( b \)
Based on the given x-intercepts, \( a \) is 2, because these are the values of \( x \) when \( y = 0 \). For the given y-intercepts, \( b \) is \( \frac{1}{3} \), because these are the values of \( y \) when \( x = 0 \).
04
Insert \( a \) and \( b \) into the Ellipse Equation
We use the values \( a = 2 \) and \( b = \frac{1}{3} \) in the standard form of the ellipse equation: \( \frac{x^2}{2^2} + \frac{y^2}{(\frac{1}{3})^2} = 1 \). This simplifies to \( \frac{x^2}{4} + 9y^2 = 1 \).
05
Simplify the Equation
The equation \( \frac{x^2}{4} + 9y^2 = 1 \) is already in a simple form. This represents the equation of the ellipse with the given intercepts.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Semi-Major Axis
The semi-major axis of an ellipse is the longest radius, stretching from the center to the farthest edge of the ellipse. Ellipses have two axes: the major and minor axes. For an ellipse centered at the origin, the major axis is aligned with either the x-axis or the y-axis. In our exercise, this alignment is with the x-axis, as evidenced by the given x-intercepts of \( \pm 2 \).
This means:
This means:
- The length of the semi-major axis, denoted as \( a \), is 2.
- The total length of the major axis is \( 2a = 4 \).
Semi-Minor Axis
The semi-minor axis is the half-length of the shortest diameter of an ellipse, extending from the center to the ellipse's edge. In our problem, we can determine the semi-minor axis using the y-intercepts. The given y-intercepts are \( \pm \frac{1}{3} \), indicating that the minor axis aligns with the y-axis. Therefore:
- The length of the semi-minor axis, denoted as \( b \), is \( \frac{1}{3} \).
- The entire minor axis thus measures \( 2b = \frac{2}{3} \).
Intercepts
Intercepts occur where the ellipse touches the x-axis and y-axis, indicating the points \( (x, 0) \) and \( (0, y) \) respectively. Working with an ellipse whose center is at the origin simplifies determining these points.
For our ellipse:
For our ellipse:
- The x-intercepts are \( \pm 2 \), where \( y = 0 \). These occur at points \( (2, 0) \) and \( (-2, 0) \).
- The y-intercepts are \( \pm \frac{1}{3} \), where \( x = 0 \). These occur at points \( (0, \frac{1}{3}) \) and \( (0, -\frac{1}{3}) \).