Chapter 1: Problem 63
Simplify the expression, and rationalize the denominator when appropriate. \(\sqrt{9 x^{-4} y^{6}}\)
Short Answer
Expert verified
Simplified expression: \(3x^{-2}y^{3}\). No rationalization needed.
Step by step solution
01
Break Down the Square Root
The expression inside the square root is \(9x^{-4}y^{6}\). We can distribute the square root over the product: \(\sqrt{9} \times \sqrt{x^{-4}} \times \sqrt{y^{6}}\).
02
Simplify Each Component
Calculate the square root of each component:- \(\sqrt{9} = 3\)- \(\sqrt{x^{-4}} = x^{-2}\) since \(\sqrt{x^{-4}} = (x^{-4})^{1/2} = x^{-2}\)- \(\sqrt{y^{6}} = y^{3}\) because \(y^{6}\) can be broken into \((y^{3})^{2}\).
03
Combine the Simplified Parts
Combine the results from Step 2 to form the expression: \(3x^{-2}y^{3}\).
04
Rationalize the Expression if Needed
In this case, since there's no square root in the denominator, no additional rationalization is needed.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rationalizing the Denominator
Rationalizing the denominator is a technique used to eliminate radicals, such as square roots, from the bottom part (denominator) of a fraction. This makes expressions easier to work with and simplifies them for further mathematical operations. When a rational number is in the denominator, it is preferable in many mathematical contexts to have a whole number or a simpler rational form. Here's how you can achieve that:
- Multiply both the numerator and the denominator by the conjugate of the denominator if it is a binomial involving a square root.
- If it's a single term like \(\frac{1}{\sqrt{a}}\), multiply the numerator and denominator by \(\sqrt{a}\) to get \(\frac{\sqrt{a}}{a}\).
Square Roots
The concept of square roots is pivotal for simplifying expressions involving powers. A square root of a number is a value that, when multiplied by itself, gives that number. For example, the square root of 9 is 3 because \(3 \times 3 = 9.\)Understanding how to work with square roots can help make expressions more manageable. Here's a breakdown of handling square roots in the expression \(\sqrt{9 x^{-4} y^{6}}\):
- Distributing the square root over multiplication: You can split the square root of a product into the product of square roots, making it easier to tackle complex expressions. For instance, \(\sqrt{9 x^{-4} y^{6}}\) becomes \(\sqrt{9} \times \sqrt{x^{-4}} \times \sqrt{y^{6}}\).
- Evaluating each square root: Simplify the expression by calculating each square root. \(\sqrt{9}=3\), \(\sqrt{x^{-4}} = x^{-2}\) using the property \((x^{m})^n = x^{m \cdot n}\), and \(\sqrt{y^{6}} = y^{3}\).
Exponent Rules
Exponent rules are essential for working with expressions that involve powers and roots, such as the one in the exercise, \(\sqrt{9x^{-4}y^{6}}\). Here are the core exponent rules that are helpful:
- Product of Powers Rule: When multiplying like bases, add the exponents. For example, \(a^m \times a^n = a^{m+n}.\)
- Power of a Power Rule: When you raise a power to another power, multiply the exponents. For example, \((a^m)^n = a^{m \cdot n}.\)
- Negative Exponent Rule: A negative exponent indicates the reciprocal of the base raised to the positive exponent: \(a^{-m} = \frac{1}{a^m}.\)