/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Factor the polynomial. $$x^{8}... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor the polynomial. $$x^{8}-16$$

Short Answer

Expert verified
The polynomial factors as \((x^4 + 4)(x^2 + 2)(x^2 - 2)\).

Step by step solution

01

Recognize the Difference of Squares

Recognize that the polynomial \(x^8 - 16\) can be written as a difference of squares. The expression is equivalent to \((x^4)^2 - 4^2\). This allows us to factor the polynomial using the difference of squares formula, \(a^2 - b^2 = (a + b)(a - b)\).
02

Apply the Difference of Squares Formula

Apply the difference of squares formula to \( (x^4)^2 - 4^2 \), which results in \((x^4 + 4)(x^4 - 4)\).
03

Further Factor the Polynomial

Notice that \(x^4 - 4\) is another difference of squares, since it can be written as \((x^2)^2 - 2^2\). Therefore, apply the difference of squares formula again to get \((x^2 + 2)(x^2 - 2)\).
04

Write the Final Factored Form

Combine all the factors. The polynomial \(x^8 - 16\) is factored completely as \((x^4 + 4)(x^2 + 2)(x^2 - 2)\). Note that \(x^4 + 4\) does not factor further over the reals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
The concept of the Difference of Squares is a powerful algebraic tool that simplifies the factoring of certain polynomials. It's based on the identity:
  • \(a^2 - b^2 = (a + b)(a - b)\)
This formula works because when you apply it, the middle terms cancel each other out, leaving you with a simple subtraction of squares.
In the context of the polynomial \(x^8 - 16\), we first recognized it as \((x^4)^2 - 4^2\). Identifying such expressions is key when using the difference of squares technique.
\((x^4)^2 - 4^2\) can be decomposed using the formula, resulting in \((x^4 + 4)(x^4 - 4)\).
This ability to break down complex expressions into simpler factors is what makes the difference of squares method an essential technique in algebra.
Polynomial Factoring
Polynomial factoring is the process of expressing a polynomial as a product of simpler polynomials. This is crucial in solving polynomial equations, simplifying expressions, and understanding polynomial behavior.
Different methods exist for polynomial factoring, and choosing the appropriate one depends on the polynomial's form.
For \(x^8 - 16\), after using the difference of squares to get \((x^4 + 4)(x^4 - 4)\), further analysis of \(x^4 - 4\) reveals another layer of factoring potential.
  • We rewrite \(x^4 - 4\) as \((x^2)^2 - (2)^2\), which is again a difference of squares.
  • Applying the same method gives us \((x^2 + 2)(x^2 - 2)\).
The final factored form \((x^4 + 4)(x^2 + 2)(x^2 - 2)\) illustrates how starting from a complex polynomial, we can use systematic factoring methods to simplify into more manageable expressions.
Algebraic Expressions
Understanding algebraic expressions is fundamental to mastering algebraic manipulations. An algebraic expression consists of variables, constants, and operational symbols that together represent a mathematical reality.
Expressions can often be simplified, factored, or expanded depending on what is needed.
  • For example, in the expression \(x^8 - 16\), we began with recognizing its structure as a difference of squares, which is a particular type of algebraic expression.
  • This recognition allowed us to apply factoring techniques efficiently.
Grasping the characteristics of different types of algebraic expressions, like polynomials, can be incredibly useful.
With practice, identifying these can become intuitive, making problem-solving much more straightforward. Always remember when dealing with algebraic expressions to look for patterns or special forms such as the difference of squares.

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Most popular questions from this chapter

The table contains average annual temperatures for the northern and southern hemispheres at various latitudes. $$\begin{array}{|c|c|c|}\hline \text { Latitude } & \text { N. hem. } & \text { S. hem. } \\\\\hline 85^{\circ} & -8^{\circ} \mathrm{F} & -5^{\circ} \mathrm{F} \\\\\hline 75^{\circ} & 13^{\circ} \mathrm{F} & 10^{\circ} \mathrm{F} \\\\\hline 65^{\circ} & 30^{\circ} \mathrm{F} & 27^{\circ} \mathrm{F} \\\\\hline 55^{\circ} & 41^{\circ} \mathrm{F} & 42^{\circ} \mathrm{F} \\\\\hline 45^{\circ} & 57^{\circ} \mathrm{F} & 53^{\circ} \mathrm{F} \\\\\hline 35^{\circ} & 68^{\circ} \mathrm{F} & 65^{\circ} \mathrm{F} \\\\\hline 25^{\circ} & 78^{\circ} \mathrm{F} & 73^{\circ} \mathrm{F} \\\\\hline 15^{\circ} & 80^{\circ}\mathrm{F} & 78^{\circ} \mathrm{F} \\\\\hline 5^{\circ} & 79^{\circ} \mathrm{F} & 79^{\circ} \mathrm{F} \\\\\hline\end{array}$$ (a) Which of the following equations more accurately predicts the average annual temperature in the southern hemisphere at latitude \(L ?\) (1) \(T_{1}=-1.09 L+96.01\) (2) \(T_{2}=-0.011 L^{2}-0.126 L+81.45\) (b) Approximate the average annual temperature in the southern hemisphere at latitude \(50^{\circ} .\)

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