/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Write the expression in the form... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the expression in the form \(a+b i,\) where \(a\) and \(b\) are real numbers. $$\frac{5}{2-7 i}$$

Short Answer

Expert verified
The expression is \( \frac{10}{53} + \frac{35}{53}i \).

Step by step solution

01

Identify the task

We need to write the expression \( \frac{5}{2-7i} \) in the form \( a + bi \), where \( a \) and \( b \) are real numbers. This involves simplifying the complex fraction.
02

Determine the conjugate

The denominator is \( 2-7i \). The conjugate is \( 2+7i \). We'll multiply both the numerator and the denominator by this conjugate to eliminate the imaginary part in the denominator.
03

Multiply numerator and denominator by the conjugate

Multiply \( 5 \) and \( 2-7i \) by the conjugate \( 2+7i \): \[\frac{5(2+7i)}{(2-7i)(2+7i)}\] This results in a fraction involving the product of two complex numbers.
04

Apply the difference of squares

The denominator \( (2-7i)(2+7i) \) is the difference of squares: \[4 - (7i)^2 = 4 + 49 = 53\] Thus, the denominator simplifies to \( 53 \).
05

Distribute in the numerator

Distribute the 5 in the numerator: \[5(2+7i) = 10 + 35i\]
06

Construct the simplified form

Combine the results from Steps 4 and 5 to write the complex number over the real denominator: \[\frac{10 + 35i}{53}\]
07

Split into real and imaginary components

Rewrite the expression as separate fractions for the real and the imaginary parts: \[\frac{10}{53} + \frac{35}{53}i\] This is in the form \( a + bi \), with \( a = \frac{10}{53} \) and \( b = \frac{35}{53} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conjugate of Complex Numbers
The concept of conjugates is crucial when dealing with complex numbers. Given a complex number in the form of \( a + bi \), the conjugate is \( a - bi \). Essentially, it involves changing the sign of the imaginary component. This can be particularly helpful in simplifying expressions with complex numbers, especially when they appear in denominators.

Using the conjugate of a complex number allows us to utilize the property that the product of a complex number and its conjugate yields a real number. For a complex number \( z = a + bi \), the product of \( z \) and its conjugate \( \overline{z} = a - bi \) simplifies as follows:

\[ z \times \overline{z} = (a + bi)(a - bi) = a^2 - (bi)^2 = a^2 + b^2 \]
This result is always real and is equal to the sum of the squares of the real and imaginary parts. In the example given, where we have \( \frac{5}{2-7i} \), multiplying numerator and denominator by the conjugate \( 2+7i \) ensures the imaginary unit \( i \) is eliminated from the denominator.
Simplifying Complex Fractions
Simplifying complex fractions requires a structured approach to remove the imaginary part in the denominator. The original problem, \( \frac{5}{2-7i} \), is simplified through multiplying both the numerator and denominator by the conjugate of the denominator.

By converting the denominator into a real number using the difference of squares, we made the division more straightforward. Here’s the quick process:
  • Identify the complex number in the denominator: \( 2 - 7i \).
  • Find the conjugate: \( 2 + 7i \).
  • Multiply both parts of the fraction by the conjugate:
    \[ \frac{5(2+7i)}{(2-7i)(2+7i)} \]
  • Apply the difference of squares to the denominator:
    \[ (2-7i)(2+7i) = 4 - (7i)^2 = 4 + 49 = 53 \]
  • Simplify the numerator: \( 5(2 + 7i) = 10 + 35i \).
This process brings the fraction to \( \frac{10 + 35i}{53} \), allowing us to clearly separate the real and imaginary components.
Imaginary Unit
The imaginary unit, denoted by \( i \), is a mathematical concept used to extend the real number system. It is defined through the equation \( i^2 = -1 \). This allows for the existence of complex numbers, which include both a real part and an imaginary part.

Complex numbers are written in the form \( a + bi \), where \( a\) and \( b \) are real numbers. The imaginary unit \( i \) is what distinguishes a complex number from a purely real number.

In the process of simplifying complex fractions, knowing the properties of \( i \) is key. When you square \( i \), you get \( -1 \), which plays a crucial role in converting complex components into real numbers by utilizing squares and conjugates. In our example, when calculating \((2-7i)(2+7i)\), you'll notice the imaginary component squared \( (7i)^2 = -49 \), turning into a real number which is positive when further simplified:
\[ 4 - 49(-1) = 4 + 49 = 53 \].
This step is vital for treating complex fractions intuitively, bringing the entire expression into the desired form with ease.

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Most popular questions from this chapter

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