Chapter 1: Problem 19
Factor the polynomial. $$x^{4}-4 x^{2}$$
Short Answer
Expert verified
The polynomial factors as \(x^2(x-2)(x+2)\).
Step by step solution
01
Identify Common Factors
The polynomial given is \(x^4 - 4x^2\). Start by looking for common factors in each term. Both terms have \(x^2\) as a factor, so factor \(x^2\) out of each term: \(x^4 = x^2 \cdot x^2\) and \(4x^2 = x^2 \cdot 4\). Thus, we can write: \(x^4 - 4x^2 = x^2(x^2 - 4)\).
02
Recognize the Difference of Squares
Notice that the expression inside the parentheses, \(x^2 - 4\), is a difference of squares. Recall that \(a^2 - b^2 = (a-b)(a+b)\). Here, \(x^2 - 4\) can be rewritten as \((x)^2 - (2)^2\).
03
Factor the Difference of Squares
Apply the difference of squares formula to factor \(x^2 - 4\). Replace \((x)^2 - (2)^2\) with \((x-2)(x+2)\). This gives us: \(x^2(x-2)(x+2)\).
04
Final Factored Form
The complete factorization of the original polynomial \(x^4 - 4x^2\) is \(x^2(x-2)(x+2)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of squares
When factoring polynomials, especially quadratic ones, recognizing a difference of squares can be immensely helpful. A difference of squares is a special case where two square numbers are subtracted. The expression takes the form \(a^2 - b^2\). The beauty of this pattern is that it can always be factored into \((a - b)(a + b)\).
Why does this work? Multiplying \((a - b)(a + b)\) results in:
In the context of our exercise, the expression \(x^2 - 4\) is a classic example. Here, \(x^2\) is a square term, and \(4\) is \((2)^2\), making it a difference of squares. Therefore, it can be factored as \((x-2)(x+2)\). This step is critical for breaking down more complex polynomials into easier parts.
Why does this work? Multiplying \((a - b)(a + b)\) results in:
- \((a-b)(a+b) = a^2 + ab - ab - b^2\)
In the context of our exercise, the expression \(x^2 - 4\) is a classic example. Here, \(x^2\) is a square term, and \(4\) is \((2)^2\), making it a difference of squares. Therefore, it can be factored as \((x-2)(x+2)\). This step is critical for breaking down more complex polynomials into easier parts.
Common factors
Finding common factors is often the first step in simplifying any polynomial. A common factor is a number or expression that divides each term in the polynomial without a remainder. It acts like a "glue" that binds terms together.
In our example, \(x^4 - 4x^2\), the common factor between both terms is \(x^2\). Each term in the expression shares at least two \(x\) factors (i.e., \(x^2\)). Recognizing this, we factor \(x^2\) out of each term:
In our example, \(x^4 - 4x^2\), the common factor between both terms is \(x^2\). Each term in the expression shares at least two \(x\) factors (i.e., \(x^2\)). Recognizing this, we factor \(x^2\) out of each term:
- \(x^4 = x^2 \cdot x^2\)
- \(4x^2 = x^2 \cdot 4\)
Factoring polynomials
Factoring polynomials is like finding the pieces of a puzzle to express a polynomial as a product of simpler expressions. This skill is foundational in algebra and helps in solving equations, simplifying expressions, and understanding functions.
When approaching a problem like \(x^4 - 4x^2\), begin by examining each term individually. First, check for common factors to simplify the expression. In our example, factoring out \(x^2\) simplifies the polynomial to \(x^2(x^2 - 4)\).
Next, use pattern recognition techniques, such as identifying a difference of squares. This allows you to break down even more complex expressions. The expression \(x^2 - 4\) is a difference of squares and can be factored into \((x-2)(x+2)\).
So, the entire polynomial \(x^4 - 4x^2\) is factored into \(x^2(x-2)(x+2)\). Understanding these steps and recognizing these patterns makes the process of factoring much more manageable, providing clarity and efficiency in solving polynomial equations.
When approaching a problem like \(x^4 - 4x^2\), begin by examining each term individually. First, check for common factors to simplify the expression. In our example, factoring out \(x^2\) simplifies the polynomial to \(x^2(x^2 - 4)\).
Next, use pattern recognition techniques, such as identifying a difference of squares. This allows you to break down even more complex expressions. The expression \(x^2 - 4\) is a difference of squares and can be factored into \((x-2)(x+2)\).
So, the entire polynomial \(x^4 - 4x^2\) is factored into \(x^2(x-2)(x+2)\). Understanding these steps and recognizing these patterns makes the process of factoring much more manageable, providing clarity and efficiency in solving polynomial equations.