/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Simplify. $$\frac{\left(2 x^{3... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify. $$\frac{\left(2 x^{3}\right)\left(3 x^{2}\right)}{\left(x^{2}\right)^{3}}$$

Short Answer

Expert verified
\(\frac{6}{x}\)

Step by step solution

01

Apply the Power of a Power Property

The expression \((x^2)^3\) can be simplified using the power of a power property, which states \((a^m)^n = a^{m imes n}\). Hence, \((x^2)^3 = x^{2 \times 3} = x^6\). This simplifies the denominator to \(x^6\).
02

Multiply the Numerator Terms

Apply the multiplication property for exponents where \(a^m \cdot a^n = a^{m+n}\). Multiply the terms in the numerator: \((2x^3)\) and \((3x^2)\). When multiplying these terms: - The coefficient terms \(2\) and \(3\) multiply to give \(6\).- The exponents of \(x\) add: \(x^3 \cdot x^2 = x^{3+2} = x^5\).Thus, the numerator becomes \(6x^5\).
03

Simplify the Fraction

Now, simplify the complete fraction \(\frac{6x^5}{x^6}\). Apply the division property of exponents \(a^m \div a^n = a^{m-n}\). Therefore, divide the exponents of \(x\): \(x^5 \div x^6 = x^{5-6} = x^{-1}\). The simplified expression is \(\frac{6}{x}\).
04

Final Simplified Expression

The fraction \(\frac{6}{x}\) is already in its simplest form, where all possible simplifications for the expression involved have been utilized. The entire original expression simplifies to \(\frac{6}{x}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simplifying Expressions
When working with mathematical expressions, simplifying them is a key skill that helps make calculations more straightforward and less error-prone. Simplifying involves reducing an expression to its most basic form. This means eliminating unnecessary parentheses, combining like terms, and using mathematical properties correctly. In the context of exponentiation, simplifying ensures that expressions are easy to work with and understand. It reduces the number of terms and operations, highlighting the essential components of the expression. For instance, in the problem at hand, we start by addressing individual components of the expression both in the numerator and the denominator before putting everything together. Keep an eye out for: - Terms with the same base that can be simplified using multiplication or division. - Constants multiplied or divided alongside variables. Simplifying like this makes it easier to see relationships between terms and grasp the core of the problem.
Power of a Power Property
The Power of a Power Property is crucial when dealing with expressions that involve exponentiation, especially with nested exponents. This property states that when you have an exponent raised to another exponent like \( (a^m)^n \), it can be simplified by multiplying the exponents: \( a^{m \times n} \). Imagine it as stacking power upon power, each stacking influencing the base at the level of multiplication of their exponents. For our exercise:- We encounter \( (x^2)^3 \) in the denominator.- Applying the power of a power property, it becomes \( x^{2 \times 3} = x^6 \).Knowing how to apply this property efficiently simplifies many tasks involving powers, thus reducing complexity. Remember to always multiply inner and outer exponents; it transforms how one handles multi-layer exponent scenarios.
Multiplication of Exponents
Multiplying terms with exponents is a common step in simplifying expressions. The multiplication property for exponents states that when bases are the same, you can add the exponents together: \( a^m \cdot a^n = a^{m+n} \).In our exercise, we multiply terms in the numerator: \( (2x^3)(3x^2) \). Let's break it down:- First, multiply the constant coefficients 2 and 3, resulting in 6.- Next, apply the exponent multiplication property: since both terms involve the base \( x \), combine them via addition: \( x^3 \cdot x^2 = x^{3+2} = x^5 \).- The result for the numerator is \( 6x^5 \).Understanding this property is crucial for simplifying expressions correctly. It's a powerful tool to streamline expressions, making them easier to interpret and solve. Always check that the bases are identical before applying this property.

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Most popular questions from this chapter

Choose the equation that best describes the table of data. (Hint: Make assignments to \(\mathbf{Y}_{\mathbf{r}}-\mathbf{Y}_{\mathbf{4}}\) and examine a table of their values.) $$\begin{array}{|c|c|}\hline x & y \\\\\hline 1 & 0.8 \\\\\hline 2 & -0.4 \\\\\hline 3 & -1.6 \\\\\hline 4 & -2.8 \\\\\hline 5 & -4.0 \\\\\hline\end{array}$$ (1) \(y=-1.2 x+2\) (2) \(y=-1.2 x^{2}+2\) (3) \(y=0.8 \sqrt{x}\) (4) \(y=x^{3 / 4}-0.2\)

The temperature \(T\) (in "C) at which water boils is related to the elevation \(h\) (in meters above sea level) by the formula $$h=1000(100-T)+580(100-T)^{2}$$ for \(95 \leq T \leq 100.\) (a) At what elevation does water boil at a temperature of \(98^{\circ} \mathrm{C} ?\) (b) The elevation of Mt. Everest is approximately 8840 meters. Estimate the temperature at which water boils at the top of this mountain. (Hint: Use the quadratic formula with \(x=100-T\).)

Simplify the expression, and rationalize the denominator when appropriate. $$\sqrt[5]{\frac{3 x^{11} y^{3}}{9 x^{2}}}$$

In evaluating negative numbers raised to fractional powers, it may be necessary to evaluate the root and integer power separately. For example, \((-3)^{2 / 5}\) can be evaluated successfully as \(\left[(-3)^{15}\right]^{2}\) or \(\left[(-3)^{2}\right]^{1 / 3}\), whereas an error message might otherwise appear. Approximate the real number expression to four decimal places. (a) \((-1.2)^{37}\) (b) \((-5.08)^{7 / 3}\)

Simplify the expression, and rationalize the denominator when appropriate. $$\frac{1}{\sqrt[3]{2}}$$

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