Chapter 5: Problem 25
Verify each identity. $$\frac{\sin t}{\csc t}+\frac{\cos t}{\sec t}=1$$
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Chapter 5: Problem 25
Verify each identity. $$\frac{\sin t}{\csc t}+\frac{\cos t}{\sec t}=1$$
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Will help you prepare for the material covered in the next section. $$\text { Solve: } u^{2}-u-1=0$$
Will help you prepare for the material covered in the next section. Use the appropriate values from Exercise 101 to answer each of the following. a. Is \(\sin \left(30^{\circ}+60^{\circ}\right),\) or \(\sin 90^{\circ},\) equal to \(\sin 30^{\circ}+\sin 60^{\circ} ?\) b. Is \(\sin \left(30^{\circ}+60^{\circ}\right),\) or \(\sin 90^{\circ},\) equal to \(\sin 30^{\circ} \cos 60^{\circ}+\cos 30^{\circ} \sin 60^{\circ} ?\)
Use this information to solve. A ball on a spring is pulled 4 inches below its rest position and then released. After t seconds, the balls distance, \(d\), in inches from its rest position is given by $$d=-4 \cos \frac{\pi}{3} t$$ Find all values of \(t\) for which the ball is 2 inches below its rest position.
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. The equation \(\tan x=\frac{\pi}{2}\) has no solution.
Use this information to solve. When throwing an object, the distance achieved depends on its initial velocity, \(v_{0}\) and the angle above the horizontal at which the object is thrown, \(\theta\) The distance, \(d\), in feet, that describes the range covered is given by $$d=\frac{v_{0}^{2}}{16} \sin \theta \cos \theta$$ where \(v_{0}\) is measured in feet per second. You and your friend are throwing a baseball back and forth. If you throw the ball with an initial velocity of \(v_{0}=90\) feet per second, at what angle of elevation, \(\theta,\) to the nearest degree, should you direct your throw so that it can be easily caught by your friend located 170 feet away?
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