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Use the most appropriate method to solve each equation on the interval \([0,2 \pi) .\) Use exact values where possible or give approximate solutions correct to four decimal places. $$2 \tan ^{2} x+5 \tan x+3=0$$

Short Answer

Expert verified
The solutions for the given exercise are \(x = 3\pi/4, 7\pi/4, 2.678\).

Step by step solution

01

Recognize the form of the equation

This exercise requires solving the quadratic equation \(2 \tan^{2}x + 5 \tan x + 3 = 0\). This is a quadratic equation in the form \(ax^2 + bx + c = 0\), where \(a = 2\), \(b = 5\), and \(c = 3\), and \(x\) is \(\tan x\).
02

Factor the equation

The quadratic equation can be factored into two binomial equations:\n\(2 \tan^{2}x + 5 \tan x + 3 = 0\) factors to \((\tan x + 1)(2\tan x + 3) = 0\).
03

Solve for x

Set each factor equal to zero and solve for \(\tan x\):\nIf \(\tan x + 1 = 0\), then \(\tan x = -1\), the solutions in the given interval are \(x = 3\pi/4, 7\pi/4\). \nIf \(2\tan x + 3 = 0\), then \(\tan x = -3/2\). This is not a standard value so we apply the arctangent function. The solution in the given interval is \(x \approx 2.678\).
04

Check the solutions

The solutions can be verified by substituting them back into the original equation. If equal to zero, they are the correct solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equation in Trigonometry
When you encounter a quadratic equation in trigonometry, it’s essential to recognize that its structure mirrors that of standard quadratic equations. These equations will have a form similar to a regular quadratic, such as \(ax^2 + bx + c = 0\), but with a trigonometric function taking the place of the variable \(x\). In our example, \(2 \tan^{2}x + 5 \tan x + 3 = 0\), \( \tan x\) replaces \(x\).

This substitution means we must apply the same principles we would for solving a quadratic equation. To solve for \(x\), we initially find the values of the trigonometric function (\( \tan x\)) that satisfy the equation, as demonstrated in the example. Once these are known, we can determine the angle \(x\) that corresponds with the identified tangent values within the given interval, in this case, \( [0,2\pi) \).

It is also beneficial to utilize the quadratic formula, \( x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\), in scenarios where factoring is not feasible. This formula still applies even when the variable \(x\) is replaced with a trigonometric function. Understanding the relationship between the trigonometric function and the quadratic equation allows for more efficient solving of these kinds of trigonometric equations.
Factoring Equations
The process of factoring is an effective method for solving quadratic equations, including those in trigonometry. To factor an equation is to break it down into simpler binomial or polynomial expressions that, when multiplied, recreate the original equation. Our example equation, \(2 \tan^{2}x + 5 \tan x + 3 = 0\), was factored into \( (\tan x + 1)(2\tan x + 3) = 0\), which simplifies the problem into finding the roots of the equation.

Zero product property is then employed; it states that if the product of two expressions is zero, then at least one of the expressions must be zero. This leads to setting \( \tan x + 1 = 0\) and \( 2\tan x + 3 = 0\), separately, and solving for \( \tan x\). Factoring is generally faster than other methods, such as completing the square or using the quadratic formula, particularly when dealing with numbers that lend themselves well to factorization.

Sometimes, recognizing the possible factors requires practice. The commonly advised method is to look for a pair of factors of the last term (in this case, 3) whose sum (when properly weighted by the coefficient of the first term, here 2) equals the middle coefficient (5). This approach can substantially decrease the complexity of trigonometric equations and is a crucial technique for students to master.
Tangent Function
The tangent function, denoted as \( \tan x\), is a fundamental trigonometric function that helps to solve equations within trigonometry. The tangent of an angle in a right triangle is the ratio of the length of the opposite side to the length of the adjacent side. In the context of the unit circle, it's the slope of the terminal side.

In solving trigonometric equations, sometimes \( \tan x\) has a value that is not one of the standard angle tangents, like in the step where we found \( \tan x = -3/2\). This is where the inverse tangent function, \( \arctan x\), comes into play, allowing us to determine an angle whose tangent is \( -3/2\). It's important to note that this inverse function will give us a principal value, and we must determine if additional solutions exist within the specified interval.

Moreover, understanding the properties of the tangent function, such as its periodicity and symmetry, can greatly assist in solving equations. Since tangent has a period of \(\pi\), it repeats its values every \(\pi\) radians. For exact values of \( \tan x\), one often looks into angles associated with the special triangles (30-60-90 or 45-45-90) or refers to the unit circle. Familiarity with these values and properties permits a more intuitive resolution of trigonometric equations.

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