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Determine the amplitude and period of each function. Then graph one period of the function. $$y=\sin 4 x$$

Short Answer

Expert verified
The amplitude of the function \(y=\sin 4x\) is 1, and the period of the function is \(\frac{Ï€}{2}\). A graph of one period of this function would start at (0,0), reach its peak at (\(\frac{Ï€}{8}\), 1), return to the x-axis at (\(\frac{Ï€}{4}\), 0), reach its minimum at (\(\frac{3Ï€}{8}\), -1), and complete the period at (\(\frac{Ï€}{2}\), 0).

Step by step solution

01

Identify the Amplitude

The amplitude of a function is the maximum or minimum value the function can reach. For the given function \(y = \sin 4x\), the coefficient in front of the sine is 1 (as there is no explicit number). Therefore, the amplitude of this function is 1.
02

Identify the Period

The period of a sine or cosine function is given by dividing the standard period (2Ï€) by the absolute value of the coefficient in front of x, inside the function. For the given function \(y = \sin 4x\), we have a coefficient of 4 in front of x. The standard period would be \(T = \frac{2Ï€}{|4|}= \frac{Ï€}{2}\). Therefore, the period of this function is \(\frac{Ï€}{2}\).
03

Graph the Function

To graph the function \(y = \sin 4x\), plot the points corresponding to one period of the function. Since we have the period as \(\frac{Ï€}{2}\), we start at x=0 and span x-values till \(\frac{Ï€}{2}\). The sine function begins with (0, 0), reaches its maximum at \(\frac{1}{4}\) of its period, returns to zero at half of its period, reaches its minimum at \(\frac{3}{4}\) of its period, and then returns back to zero completing its period. Applying this understanding to the current function, plot (0,0), then move to \(\frac{Ï€}{8}\) where y=1, at \(\frac{Ï€}{4}\) y returns to 0, at \(\frac{3Ï€}{8}\) y=-1 and finally y returns to 0 at \(\frac{Ï€}{2}\). Connecting these dots will create a complete graph for one period of \(y = \sin 4x\).

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