/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 In Exercises \(61-86,\) use refe... [FREE SOLUTION] | 91Ó°ÊÓ

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In Exercises \(61-86,\) use reference angles to find the exact value of each expression. Do not use a calculator. $$\tan \left(-\frac{\pi}{6}\right)$$

Short Answer

Expert verified
\(\tan(-\pi/6) = -\sqrt{3}/3\).

Step by step solution

01

Identify the reference angle

The problem contains a negative angle, so the reference angle we are looking to find is the positive version of this angle. Thus, reference angle = π/6. It is helpful to remember that π radians equal 180° in degrees.
02

Determine the quadrant of the given angle

The given angle is negative, which means we are going clockwise from the initial side. Therefore, the angle -Ï€/6 is in the 4th quadrant of the unit circle.
03

Use the reference angle to find the exact value

In the 4th quadrant, the tangent function is negative. Hence, \(\tan(-\pi/6) = -\tan(\pi/6)\). Now, from the trigonometric values know that \(\tan(\pi/6) = \sqrt{3}/3\). Then, apply the negative value to this result because the angle is in the 4th quadrant.

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