/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 73 In Exercises \(61-86,\) use refe... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(61-86,\) use reference angles to find the exact value of each expression. Do not use a calculator. $$\sin \left(-240^{\circ}\right)$$

Short Answer

Expert verified
The exact value of \(\sin(-240^{\circ})\) is \(\sqrt{3}/2\).

Step by step solution

01

Convert the angle to a positive measure

An angle of \(-240^{\circ}\) actually moves in the clockwise direction. To convert it to a positive measure, add \(360^{\circ}\) to it. Therefore, the angle measured in the counterclockwise direction will be \( 360^{\circ}-240^{\circ}=120^{\circ}\)
02

Find the reference angle

A reference angle is always computed relative to the x-axis in the clockwise direction. For an angle of \(120^{\circ}\), the reference angle would be \( 180^{\circ}-120^{\circ}=60^{\circ}\)
03

Use the reference angle to find exact sine value

The angle \(120^{\circ}\) lies in the 2nd quadrant where sine is positive. The Sine of \(60^{\circ}\) is \(\sqrt{3}/2\). Therefore, \(\sin(-240^{\circ}) = \sin(120^{\circ}) = \sin(60^{\circ}) = \sqrt{3}/2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.