/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Determine the amplitude and peri... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the amplitude and period of each function. Then graph one period of the function. $$y=-\sin \frac{4}{3} x$$

Short Answer

Expert verified
The amplitude of the function \( -\sin \frac{4}{3} x \) is 1 and the period is \( \frac{3\pi}{2} \).

Step by step solution

01

Determining the Amplitude

The amplitude is the absolute value of the coefficient of the sin part. So in the given function \( -\sin \frac{4}{3} x \), the amplitude is \( |-1| = 1 \).
02

Determining the Period

The period is obtained by dividing \(2\pi\) by the absolute value of the coefficient of the x. So in the given function \( -\sin \frac{4}{3} x \), the period is \( \frac {2\pi}{\left |\frac{4}{3} \right |} = \frac{2\pi \times 3}{4} = \frac{3\pi}{2} \).
03

Graphing the Function

The graph of one period of the function will have the form of a sine wave with a height (peak to trough) of 1 (amplitude) and a length (left to right) of \( \frac{3\pi}{2} \) (period). It will be a downward wave (negative) because of the negative coefficient on the sin function.

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