/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 This will help you prepare for t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

This will help you prepare for the material covered in the first section of the next chapter. $$\text { Simplify: } \frac{17 \pi}{6}-2 \pi$$

Short Answer

Expert verified
The simplified form of \( \frac{17 \pi}{6}-2 \pi \) is \( \frac{5 \pi}{6} \).

Step by step solution

01

Identify like terms

Both of the terms \( \frac{17 \pi}{6} \) and \( -2\pi \) have \( \pi \) in them. This makes them like terms and indicates that they can be subtracted directly.
02

Rewrite 2 as a fraction with 6 as the denominator

Before subtracting, we need to ensure both terms have the same denominator. To convert 2 into a fraction with 6 as the denominator multiply top (numerator) and bottom (denominator) by 6, which gives \( \frac{12}{6} = 2 \). Therefore, we can express \( -2\pi \) as \( -\frac{12\pi}{6} \).
03

Subtract the fractions

Now, subtract the fractions \( \frac{17 \pi}{6} - \frac{12\pi}{6} \). This results in \( \frac{5 \pi}{6} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Like Terms in Algebra
When simplifying algebraic expressions, identifying like terms is crucial. Like terms are terms that have the same variable raised to the same power. In our example, both terms, \( \frac{17 \pi}{6} \) and \( -2\pi \) contain the constant \(\pi\). This makes them compatible for addition or subtraction because they both represent some multiple of \(\pi\). Much like combining apples with apples, simplifying like terms makes the calculation straightforward.

Just remember that only the coefficients (the numbers in front of the variable or constant) are combined when dealing with like terms; the variable part remains unchanged. This approach to combining like terms is a fundamental skill in algebra that enables the simplification of many expressions and equations.
Fraction Subtraction
Subtracting fractions can sometimes be intimidating, but it becomes manageable once you understand the rules. The key to fraction subtraction is having a common denominator. Imagine if you wanted to subtract two slices of pies of different sizes; it would be confusing, right? To make it simple, we ensure that the pie slices (fractions) are the same size (have the same denominator) before subtracting.

Once the denominators are the same, you only subtract the numerators (the top numbers). The common denominator remains intact. So, in our example, when we subtract \( \frac{17 \pi}{6} - \frac{12\pi}{6} \), we're effectively only subtracting 17 from 12, keeping \(\pi\) aside, to achieve the simplified result of \( \frac{5 \pi}{6} \). Understanding and confidently applying fraction subtraction is vital for tackling more complex algebraic expressions.
Converting Whole Numbers to Fractions
At times in mathematics, you might need to operate between whole numbers and fractions. To do this smoothly, you convert the whole number into a fraction. How? By choosing a denominator (the bottom part of the fraction) and multiplying both the numerator (the top part of the fraction) and the denominator by the same number, which in our case is 6.

So, when we have the whole number 2 and we want to subtract it from a fraction with a denominator of 6, we create an equivalent fraction for 2 by using \( \frac{2 \times 6}{1 \times 6} = \frac{12}{6} \). With this conversion, the whole number is now in a fractional form that can easily interact with other fractions, facilitating operations such as addition and subtraction.
Pi in Mathematical Expressions
The constant \(\pi\) (approximately equal to 3.14159) appears frequently in mathematical expressions, especially those involving circles and angles. In algebra, \(\pi\) is treated as a constant variable. This means that while we don't combine \(\pi\) numerically with other terms, it stays associated with the number it's attached to when we simplify expressions.

Consequently, in an expression like \( \frac{17 \pi}{6}-2 \pi \), \(\pi\) is the common ground that lets us combine the terms. It's essential to recognize such constants in algebraic expressions and understand their role in computations. Working with \(\pi\) reinforces the concept of addressing like terms and managing fractional operations involving constants.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I'm using a photocopier to reduce an image over and over by \(50 \%,\) so the exponential function \(f(x)=\left(\frac{1}{2}\right)^{x}\) models the new image size, where \(x\) is the number of reductions.

Each group member should consult an almanac, newspaper, magazine, or the Internet to find data that can be modeled by exponential or logarithmic functions. Group members should select the two sets of data that are most interesting and relevant. For each set selected, find a model that best fits the data. Each group member should make one prediction based on the model and then discuss a consequence of this prediction. What factors might change the accuracy of the prediction?

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I used an exponential model with a positive growth rate to describe the depreciation in my car's value over four years.

Exercises \(153-155\) will help you prepare for the material covered in the next section. U.S. soldiers fight Russian troops who have invaded New York City. Incoming missiles from Russian submarines and warships ravage the Manhattan skyline. It's just another scenario for the multi-billion-dollar video games Call of Duty, which have sold more than 100 million games since the franchise's birth in 2003 The table shows the annual retail sales for Call of Duty video games from 2004 through 2010 . Create a scatter plot for the data. Based on the shape of the scatter plot, would a logarithmic function, an exponential function, or a linear function be the best choice for modeling the data? $$\begin{array}{cc} \hline \text { Year } & \begin{array}{c} \text { Retail Sales } \\ \text { (millions of dollars) } \end{array} \\ \hline 2004 & 56 \\ 2005 & 101 \\ 2006 & 196 \\ 2007 & 352 \\ 2008 & 436 \\ 2009 & 778 \\ 2010 & 980 \end{array}$$

In parts (a)-(c), graph \(f\) and \(g\) in the same viewing rectangle. a. \(f(x)=\ln (3 x), g(x)=\ln 3+\ln x\) b. \(f(x)=\log \left(5 x^{2}\right), g(x)=\log 5+\log x^{2}\) c. \(f(x)=\ln \left(2 x^{3}\right), g(x)=\ln 2+\ln x^{3}\) d. Describe what you observe in parts (a)-(c). Generalize this observation by writing an equivalent expression for \(\log _{b}(M N),\) where \(M>0\) and \(N>0\) e. Complete this statement: The logarithm of a product is equal to____.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.