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Evaluate or simplify each expression without using a calculator. $$\log 10^{8}$$

Short Answer

Expert verified
The simplified expression of \( \log 10^{8} \) is 8.

Step by step solution

01

Identification of log properties

Firstly, identify the log property that allows you to simplify the expression. The expression is in the form \( \log_{b} b^{n} \), where b is the base number, and n is the exponent. So, according to the logarithmic property \( \log_{b} b^{n} = n \)
02

Application of log property

Apply this property to the given expression \( \log 10^{8} \). Since the base is 10 and the exponent is 8, using the property of logarithms, this expression simplifies to 8.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Properties
Logarithms are mathematical operations that help us solve equations involving exponentiation. They are the inverse operations of exponentiation, much like how subtraction is the inverse of addition. To better understand logarithms, it's essential to learn about some common logarithmic properties.

One fundamental property is the "Power Rule," which states:\[\log_{b}(b^n) = n\] This means if you have a logarithm where the base is the same as the base of the exponent inside the log, the logarithm simplifies to the exponent value directly.

This property is incredibly useful because it allows you to simplify expressions without performing complex calculations. For instance, in the original exercise \( \log 10^8 \), it fits perfectly into this rule, giving us the simplified result of 8.

Other useful properties include the "Product Rule" \((\log_b(mn) = \log_b(m) + \log_b(n))\), the "Quotient Rule" \((\log_b(\frac{m}{n}) = \log_b(m) - \log_b(n))\), and the "Change of Base Formula". These rules are powerful tools that make working with logarithms much easier.
Exponentiation
Exponentiation is a mathematical operation involving two numbers: the base and the exponent. The base is the number that is multiplied by itself a certain number of times, as indicated by the exponent. This means if we have say \(10^3\), it is equivalent to \(10 \times 10 \times 10\), which equals 1000.

Understanding exponentiation is crucial because it frequently appears in various branches of mathematics, including in problems involving growth patterns, compound interest, and even in simplifying logarithmic expressions.

When you encounter a logarithmic expression like \(\log 10^8\), you can use the properties of exponentiation together with logarithmic properties to simplify and solve the expression efficiently. Knowing that exponentiation describes repeated multiplication allows one to see how logarithms can simplify these expressions by converting multiplication into a more manageable form.
Logarithm Base 10
A logarithm with base 10 is often referred to as a "common logarithm" and is written simply as \(\log\) without specifying a base. This is because base 10 logarithms are ‘common’ in everyday scenarios, especially in the fields of science and engineering where powers of ten frequently occur.

For example, \(\log(1000)\) asks the question: "10 raised to what power equals 1000?" The answer is 3, because \(10^3 = 1000\). This makes the common logarithm extremely useful for simplifying calculations that deal with powers of ten.

These logarithms take advantage of our base 10 number system, making processes like scaling up or down through orders of magnitude intuitive and straightforward. In computational tools and calculators, the button labelled "log" almost always refers to the base 10 logarithm. In the context of the original exercise \(\log 10^8\), it signifies how easily expressions with base 10 can be manipulated using logarithmic properties.

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Most popular questions from this chapter

Hurricanes are one of nature's most destructive forces. These low-pressure areas often have diameters of over 500 miles. The function \(f(x)=0.48 \ln (x+1)+27\) models the barometric air pressure, \(f(x),\) in inches of mercury, at a distance of \(x\) miles from the eye of a hurricane. Use this function to solve Exercises \(133-134\) Use an equation to answer this question: How far from the eye of a hurricane is the barometric air pressure 29 inches of mercury? Use the \([\text { TRACE }]\) and \(\overline{\mathbf{Z O O M}}\) features or the intersect command of your graphing utility to verify your answer.

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I used an exponential model with a positive growth rate to describe the depreciation in my car's value over four years.

In parts (a)-(c), graph \(f\) and \(g\) in the same viewing rectangle. a. \(f(x)=\ln (3 x), g(x)=\ln 3+\ln x\) b. \(f(x)=\log \left(5 x^{2}\right), g(x)=\log 5+\log x^{2}\) c. \(f(x)=\ln \left(2 x^{3}\right), g(x)=\ln 2+\ln x^{3}\) d. Describe what you observe in parts (a)-(c). Generalize this observation by writing an equivalent expression for \(\log _{b}(M N),\) where \(M>0\) and \(N>0\) e. Complete this statement: The logarithm of a product is equal to____.

Each group member should consult an almanac, newspaper, magazine, or the Internet to find data that can be modeled by exponential or logarithmic functions. Group members should select the two sets of data that are most interesting and relevant. For each set selected, find a model that best fits the data. Each group member should make one prediction based on the model and then discuss a consequence of this prediction. What factors might change the accuracy of the prediction?

a. Evaluate: \(\log _{3} 81\) b. Evaluate: \(2 \log _{3} 9\) c. What can you conclude about $$ \log _{3} 81, \text { or } \log _{3} 9^{2} ? $$

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