/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 103 The formula \(A=37.3 e^{0.0095 t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The formula \(A=37.3 e^{0.0095 t}\) models the population of California, \(A,\) in millions, \(t\) years after 2010 . a. What was the population of California in \(2010 ?\) b. When will the population of California reach 40 million?

Short Answer

Expert verified
a. The population of California in 2010 was 37.3 million. b. The population of California will reach 40 million approximately at the year found by evaluating \(\frac{\ln(\frac{40}{37.3})}{0.0095}\) years after 2010.

Step by step solution

01

Identify the Population in 2010

In the given exponential growth model, the value of the population at any given time \(t\) is given by: \(A=37.3 e^{0.0095 t}\). Here, \(t\) is the number of years after 2010. Therefore, the population in 2010 would be the population when \(t = 0\). Hence, calculate \(A\) when \(t = 0\). This leads to \(A = 37.3 e^{0.0095*0} = 37.3 e^{0}\). Since \(e^{0}\) equals 1, the population was 37.3 Million in 2010.
02

Calculate When the Population Reaches 40 Million

To find out when the population will reach 40 million, we need to solve for \(t\) in the model when \(A = 40\). This gives us: \(40 = 37.3 e^{0.0095 t}\). Start solving for \(t\) by firstly dividing both sides of the equation by 37.3 to isolate the exponential term: \(\frac{40}{37.3} = e^{0.0095 t}\). Now, take the natural logarithm (ln) of both sides to eliminate \(e\): \(\ln(\frac{40}{37.3}) = 0.0095 t\). Lastly, divide by 0.0095 to find the value of \(t\): \(t = \frac{\ln(\frac{40}{37.3})}{0.0095}\). Use a calculator to compute this.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I'm using a photocopier to reduce an image over and over by \(50 \%,\) so the exponential function \(f(x)=\left(\frac{1}{2}\right)^{x}\) models the new image size, where \(x\) is the number of reductions.

Begin by graphing \(y=|x| .\) Then use this graph to obtain the graph of \(y=|x-2|+1 . \quad \text { (Section } 1.6, \text { Example } 3)\)

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I use the natural base \(e\) when determining how much money I'd have in a bank account that earns compound interest subject to continuous compounding.

Without using a calculator, find the exact value of \(\log _{4}\left[\log _{3}\left(\log _{2} 8\right)\right]\).

Use a calculator with an \(\left[e^{x}\right]\) key to solve. The bar graph shows the percentage of U.S. high school seniors who applied to more than three colleges for selected years from 1980 through 2013. (BAR GRAPH CAN'T COPY) The data can be modeled by $$ f(x)=x+31 \text { and } g(x)=32.7 e^{0.0217 x} $$ in which \(f(x)\) and \(g(x)\) represent the percentage of high school seniors who applied to more than three colleges \(x\) years after 1980\. Use these functions to solve . Where necessary, round answers to the nearest percent. In college, we study large volumes of information \(-\) information that, unfortunately, we do not often retain for very long. The function $$ f(x)=80 e^{-0.5 x}+20 $$ describes the percentage of information, \(f(x),\) that a particular person remembers \(x\) weeks after learning the information. a. Substitute 0 for \(x\) and, without using a calculator, find the percentage of information remembered at the moment it is first learned. b. Substitute 1 for \(x\) and find the percentage of information that is remembered after 1 week. c. Find the percentage of information that is remembered after 4 weeks. d. Find the percentage of information that is remembered after one year (52 weeks).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.