/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 The equation for \(f\) is given ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The equation for \(f\) is given by the simplified expression that results after performing the indicated operation. Write the equation for \(f\) and then graph the function. $$\frac{x}{2 x+6}-\frac{9}{x^{2}-9}$$

Short Answer

Expert verified
The simplified form of the given function is \(f(x) =\frac{x^{2} -3x -18}{2(x-3)(x+3)}\). The graph of this function is a hyperbola with vertical asymptotes at \(x=3\) and \(x=-3\).

Step by step solution

01

Factor the denominators

To lump these two fractions into one, we need to find a common denominator. That often involves factoring. The denominators \(2x+6\) and \(x^{2}-9\) factor as \(2(x+3)\) and \((x-3)(x+3)\) respectively. Notice that both have \(x+3\) in common, that's a good sign.
02

Combine into a single subtracted fraction

Now, we can rewrite each fraction in terms of the common denominator \((x-3)(x+3)\). Specifically, \(\frac{x}{2(x+3)}\) becomes \(\frac{x(x-3)}{2(x-3)(x+3)}\) and \(\frac{9}{(x-3)(x+3)}\) stays as it is. We can then subtract them: \(\frac{x(x-3)}{2(x-3)(x+3)} - \frac{9}{(x-3)(x+3)}\) results in \(\frac{x(x-3)-18}{2(x-3)(x+3)}\).
03

Simplify the numerator

The numerator \(x(x-3)-18\) simplifies to \(x^{2} -3x -18\). Substitute this back into the fraction from step 2.
04

Write f(x)

Finally, we write the simplified expression for f as: \(f(x) =\frac{x^{2} -3x -18}{2(x-3)(x+3)}\)
05

Graph f(x)

Plot the graph of the function \(f(x) =\frac{x^{2} -3x -18}{2(x-3)(x+3)}\). Be sure to include any relevant points, intercepts and asymptotes. Because of the x term in the denominator, there would be vertical asymptotes at \(x=3\) and \(x=-3\), and because of the \(x^{2}\) term in the numerator, the graph will be a hyperbola.

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