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Find the domain of each rational function. $$h(x)=\frac{x+8}{x^{2}-64}$$

Short Answer

Expert verified
The domain of the function \(h(x)=\frac{x+8}{x^{2}-64}\) is \((-\infty, -8) \cup (-8, 8) \cup (8, \infty)\)

Step by step solution

01

Identifying the denominator

In the function \(h(x)=\frac{x+8}{x^{2}-64}\), the denominator is \(x^{2}-64\). Set this equal to zero to find the x-values where the function will be undefined.
02

Solve for x

Solving \(x^{2}-64 = 0\) by moving 64 to the other side gives \(x^{2} = 64\). Taking the square root of both sides (remembering to consider both the positive and negative square root) gives \(x = 8\) and \(x = -8\). These are the x-values at which the function is undefined.
03

State the domain

Given that the function is undefined at \(x = 8\) and \(x = -8\), the domain of the function is all real numbers except for 8 and -8. This can be expressed as \((-\infty, -8) \cup (-8, 8) \cup (8, \infty)\)

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