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91Ó°ÊÓ

Find each product and write the result in standard form. $$(2+3 i)^{2}$$

Short Answer

Expert verified
The product of \((2 + 3i)^2\) in standard form is \(-5 + 12i\).

Step by step solution

01

Write the Expression to Square

First, write the given expression in multiplication form. \( (2 + 3i)^2 \) is equivalent to \( (2 + 3i) * (2 + 3i) \).
02

Distribute/Multiply Across

Expand the above expression by using the distributive property, also known as the FOIL method, which stands for First, Outer, Inner, and Last. \((2*2) + (2*3i) + (3i*2) + (3i*3i)\).
03

Simplify the Expression

Simplify this expression which gives \(4 + 6i + 6i - 9\), where -9 comes from simplifying \(3i * 3i\), which equals \(-3^2 = -9\) since \(i^2 = -1\).
04

Combine Like Terms

Finally, combine the like terms to present the result in standard form. \(4 - 9 + 6i + 6i \rightarrow -5 + 12i\).

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