Chapter 1: Problem 8
Find \(f(g(x))\) and \(g(f(x))\) and determine whether each pair of functions \(f\) and \(g\) are inverses of each other. $$f(x)=\frac{2}{x-5} \text { and } g(x)=\frac{2}{x}+5$$
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Chapter 1: Problem 8
Find \(f(g(x))\) and \(g(f(x))\) and determine whether each pair of functions \(f\) and \(g\) are inverses of each other. $$f(x)=\frac{2}{x-5} \text { and } g(x)=\frac{2}{x}+5$$
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Will help you prepare for the material covered in the next section. Write an algebraic expression for the fare increase if a 200 dollars plane ticket is increased to \(x\) dollars.
$$\text { Solve and check: } \frac{x-1}{5}-\frac{x+3}{2}=1-\frac{x}{4}$$
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. The function \(f(x)=5\) is one-to-one.
Determine whether each statement makes sense or does not make sense, and explain your reasoning.I used a function to model data from 1990 through 2015 .I have two functions. Function \(f\) models total world population \(x\) years after 2000 and function \(g\) models population of the world's more-developed regions \(x\) years after 2000.1 can use \(f-g\) to determine the population of the world's less-developed regions for the years in both function's domains.
Furry Finances. A pet insurance policy has a monthly rate that is a function of the age of the insured dog or cat. For pets whose age does not exceed \(4,\) the monthly cost is \(\$ 20 .\) The cost then increases by \(\$ 2\) for each successive year of the pet's age. $$\begin{array}{cc} \text { Age Not Exceeding } & \text { Monthly cost } \\ \hline 4 & \$ 20 \\ 5 & \$ 22 \\ 6 & \$ 24 \end{array}$$ The cost schedule continues in this manner for ages not exceeding \(10 .\) The cost for pets whose ages exceed 10 is \(\$ 40 .\) Use this information to create a graph that shows the monthly cost of the insurance, \(f(x),\) for a pet of age \(x,\) where the function's domain is [0,14]
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