Chapter 1: Problem 73
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. If a point is on the \(y\) -axis, its \(x\) -coordinate must be 0
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 1: Problem 73
Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. If a point is on the \(y\) -axis, its \(x\) -coordinate must be 0
All the tools & learning materials you need for study success - in one app.
Get started for free
114\. If \(f(x)=x^{2}-4\) and \(g(x)=\sqrt{x^{2}-4},\) then \((f \circ g)(x)=-x^{2}\) and \(\left(f^{\circ} g\right)(5)=-25\) 115\. There can never be two functions \(f\) and \(g\), where \(f \neq g\), for which \((f \circ g)(x)=(g \circ f)(x)\) 116\. If \(f(7)=5\) and \(g(4)=7,\) then \((f \circ g)(4)=35\) 117\. If \(f(x)=\sqrt{x}\) and \(g(x)=2 x-1,\) then \((f \circ g)(5)=g(2)\) 118\. Prove that if \(f\) and \(g\) are even functions, then \(f g\) is also an even function. 119\. Define two functions \(f\) and \(g\) so that \(f^{\circ} g=g \circ f\)
Will help you prepare for the material covered in the next section. Solve for \(y: 3 x+2 y-4=0\)
Graph both equations in the same rectangular coordinate system and find all points of intersection. Then show that these ordered pairs satisfy the equations. $$\begin{aligned}(x-2)^{2}+(y+3)^{2} &=4 \\\y &=x-3\end{aligned}$$
If you are given a function's equation, how do you determine if the function is even, odd, or neither?
Explaining the Concepts: If equations for \(f\) and \(g\) are given, explain how to find \(f-g .\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.