Chapter 1: Problem 19
Graph each equation.Let \(x=-3,-2,-1,0\) \(1,2,\) and 3 $$y=-\frac{1}{2} x$$
Short Answer
Expert verified
The line graph of the equation \(y=-\frac{1}{2}x\) has a negative slope and passes through the following points when x is -3, -2, -1, 0, 1, 2, 3: (-3, 1.5), (-2, 1), (-1, 0.5), (0,0), (1,-0.5), (2,-1), (3, -1.5).
Step by step solution
01
Understand the concept of slope
The slope of the line can be understood as the change in y for every unit increase in x. Here, the slope is -1/2, which means that for each unit increase in x, y will decrease by 1/2.
02
Calculate y-values using given x-values
Plug in the given x-values into the equation \(-\frac{1}{2}x\) to find the corresponding y-values. For example, when \(x=-3\), \(y=-\frac{1}{2}(-3)=1.5\). Similarly, calculate the y-values for \(x=-2,-1,0,1,2,3\)
03
Plot the points and draw the line
Each (x, y) pair constitutes a point on the graph. Plot these points on the graph. Once all the points have been plotted, draw a straight line (because this is a linear equation) that passes through these points. This line is the graphical representation of the equation \(y=-\frac{1}{2}x\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope of a Line
Understanding the slope of a line is crucial when graphing linear equations. In simple terms, the slope measures how steep a line is. It's often described as the rise over run, or the change in the vertical direction divided by the change in the horizontal direction. Mathematically, it’s expressed as \( m \),
In our exercise, the slope is given as \( -\frac{1}{2} \), which means for every one unit we move to the right along the x-axis, the line moves down by half a unit along the y-axis. This negative slope indicates that the line is decreasing, or going downwards as we move from left to right. A positive slope would indicate an upward trend. To visualize this, consider a hill: a negative slope represents descending down the hill, while a positive slope is akin to climbing up. The steeper the hill, the larger the absolute value of the slope.
In our exercise, the slope is given as \( -\frac{1}{2} \), which means for every one unit we move to the right along the x-axis, the line moves down by half a unit along the y-axis. This negative slope indicates that the line is decreasing, or going downwards as we move from left to right. A positive slope would indicate an upward trend. To visualize this, consider a hill: a negative slope represents descending down the hill, while a positive slope is akin to climbing up. The steeper the hill, the larger the absolute value of the slope.
Coordinate Plotting
The art of coordinate plotting is a fundamental aspect of graphing linear equations. Each point on a graph has a set of coordinates \( (x, y) \) representing its position on the Cartesian plane. The first value, \( x \), denotes the position along the horizontal x-axis, while the second value, \( y \), signifies the position along the vertical y-axis.
Plotting points correctly is vital to creating an accurate graph of a linear equation. After calculating the y-values based on the x-values we chose (\(x=-3,-2,-1,0,1,2,3\)), we note each pair of \( (x, y) \) and place a dot at that position on the graph. When all the points are on the graph, we should observe that they align to form a straight line—thanks to the linear nature of the equation we’re working with.
Plotting points correctly is vital to creating an accurate graph of a linear equation. After calculating the y-values based on the x-values we chose (\(x=-3,-2,-1,0,1,2,3\)), we note each pair of \( (x, y) \) and place a dot at that position on the graph. When all the points are on the graph, we should observe that they align to form a straight line—thanks to the linear nature of the equation we’re working with.
Linear Equation
A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a single variable. Linear equations form a straight line when graphed on a coordinate plane. The standard form of a linear equation is \( Ax + By = C \), but it can be rearranged in various ways, such as the slope-intercept form, which is often easier to use for graphing.
In our case, the equation \( y = -\frac{1}{2}x \) is already in a form that allows us to identify the slope and the y-intercept quickly. There are no exponents greater than 1, indicating that the graph will indeed be a straight line—a key characteristic of linear equations. Linear equations are straightforward to graph, analyze, and interpret, making them a fundamental building block in the study of algebra.
In our case, the equation \( y = -\frac{1}{2}x \) is already in a form that allows us to identify the slope and the y-intercept quickly. There are no exponents greater than 1, indicating that the graph will indeed be a straight line—a key characteristic of linear equations. Linear equations are straightforward to graph, analyze, and interpret, making them a fundamental building block in the study of algebra.
Slope-Intercept Form
The slope-intercept form of a linear equation is an efficient way to express these equations for graphing purposes. It is written as \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept—the point where the line crosses the y-axis. This form makes it easy to graph a linear equation because you can immediately see both the slope and the y-intercept without needing to rewrite the equation.
In our exercise, the equation \( y = -\frac{1}{2}x \) already is in slope-intercept form. Here, \( m = -\frac{1}{2} \) and \( b \) is implicitly 0 since there is no \( + b \) part in the equation. This means our line crosses the origin \( (0,0) \) and has a slope that causes it to descend half a unit for every single unit increased. Placing these key features on the graph lays the foundation for accurately drawing the line.
In our exercise, the equation \( y = -\frac{1}{2}x \) already is in slope-intercept form. Here, \( m = -\frac{1}{2} \) and \( b \) is implicitly 0 since there is no \( + b \) part in the equation. This means our line crosses the origin \( (0,0) \) and has a slope that causes it to descend half a unit for every single unit increased. Placing these key features on the graph lays the foundation for accurately drawing the line.