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Chapter 1: Problem 18

Find the domain of each function. $$f(x)=\sqrt{x+2}$$

Short Answer

Expert verified
The domain of the function \(f(x) = \sqrt{x+2}\) is \(x \geq -2\), meaning the function is defined for any real number x greater than or equal to -2.

Step by step solution

01

Write down the function

The function given is \(f(x) = \sqrt{x+2}\).
02

Set the argument under the square root greater than or equal to zero

For a function to be in the real number domain, the equation inside the square root must be greater than or equal to 0. Therefore, set the equation \(x+2 \geq 0\).
03

Solve for \(x\)

Subtract 2 from both sides of this inequality to isolate x. That gives us \(x \geq -2\).

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