Chapter 1: Problem 103
Solve for \(h: \pi r^{2} h=22 .\) Then rewrite \(2 \pi r^{2}+2 \pi r h\) in terms of \(r\).
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Chapter 1: Problem 103
Solve for \(h: \pi r^{2} h=22 .\) Then rewrite \(2 \pi r^{2}+2 \pi r h\) in terms of \(r\).
These are the key concepts you need to understand to accurately answer the question.
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Explaining the Concepts: Describe a procedure for finding ( \(f \circ g\) ) ( \(x\) ). What is the name of this function?
Furry Finances. A pet insurance policy has a monthly rate that is a function of the age of the insured dog or cat. For pets whose age does not exceed \(4,\) the monthly cost is \(\$ 20 .\) The cost then increases by \(\$ 2\) for each successive year of the pet's age. $$\begin{array}{cc} \text { Age Not Exceeding } & \text { Monthly cost } \\ \hline 4 & \$ 20 \\ 5 & \$ 22 \\ 6 & \$ 24 \end{array}$$ The cost schedule continues in this manner for ages not exceeding \(10 .\) The cost for pets whose ages exceed 10 is \(\$ 40 .\) Use this information to create a graph that shows the monthly cost of the insurance, \(f(x),\) for a pet of age \(x,\) where the function's domain is [0,14]
Solve: \(\frac{2}{x+3}-\frac{4}{x+5}=\frac{6}{x^{2}+8 x+15}\) (Section P.7, Example 3)
What is a piecewise function?
A telephone company offers the following plans. Also given are the piecewise functions that model these plans. Use this information to solve. Plan \(A\) \(\cdot \$ 30\) per month buys 120 minutes. \(\cdot\) Additional time costs \(\$ 0.30\) per minute. $$C(t)=\left\\{\begin{array}{ll}30 & \text { if } 0 \leq t \leq 120 \\\30+0.30(t-120) & \text { if } t>120 \end{array}\right. $$ Plan \(B\) \(\cdot \ 40\) per month buys 200 minutes. \(\cdot\) Additional time costs \(\$ 0.30\) per minute. $$ C(t)=\left\\{\begin{array}{ll} 40 & \text { if } 0 \leq t \leq 200 \\\ 40+0.30(t-200) & \text { if } t>200 \end{array}\right. $$ Simplify the algebraic expression in the second line of the piecewise function for plan A. Then use point-plotting to graph the function.
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