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Solve each quadratic equation by the method of your choice. $$x^{2}-2 x=1$$

Short Answer

Expert verified
The solutions to the quadratic equation \(x^{2}-2 x=1\) are \(x=1 - \sqrt{2}\) and \(x=1 + \sqrt{2}\).

Step by step solution

01

Rearrange the equation

We start by writing our equation in standard quadratic form \(ax^2+bx+c=0\). So rearrange \(x^{2}-2 x=1\) to \(x^{2}-2x-1=0\).
02

Apply the quadratic formula

The general quadratic formula is given by \(x={-b \pm \sqrt{b^{2}-4ac}} \over {2a}}\). Here, \(a=1, b=-2\), and \(c=-1\). Substituting these values in, we find the solutions \(x={2 \pm \sqrt{(-2)^{2}-4*1*-1}} \over {2*1}}\), which simplifies to \(x={2 \pm \sqrt{4+4}} \over 2}\).
03

Solve for X

Further simplifying, we find the solutions are \(x={2 \pm \sqrt{8}} \over 2} = {2 \pm 2\sqrt{2}} \over 2\). Splitting the fraction into its two solutions gives us \(x=1 \pm \sqrt{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations. A quadratic equation is any equation that can be written in the form \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants and \(a eq 0\). The quadratic formula is derived from completing the square on the general quadratic equation.

The formula itself is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]This formula finds the values of \(x\) that make the equation equal to zero. It's incredibly useful because it can solve any quadratic equation, regardless of whether the equation is easily factorable or if the roots are rational numbers.

To use the quadratic formula, you simply need to identify the coefficients \(a\), \(b\), and \(c\) from your equation, substitute them into the formula, and perform the arithmetic to find the solutions. One amazing feature of this formula is that it also tells you the nature of the roots:
  • If \(b^2 - 4ac > 0\), you have two distinct real roots.
  • If \(b^2 - 4ac = 0\), there's exactly one real root (a repeated root).
  • If \(b^2 - 4ac < 0\), the equation has two complex roots.
Understanding and mastering the quadratic formula can make solving quadratic equations straightforward and almost mechanical, taking out the guesswork involved in factoring.
Standard Quadratic Form
The term 'standard quadratic form' refers to the way of writing quadratic equations so they can be easily solved using algebraic methods like the quadratic formula.

A quadratic equation is generally expressed in the standard form as:\[ax^2 + bx + c = 0\]where \(a\), \(b\), and \(c\) are known as the coefficients of the equation, and \(a eq 0\).

Writing an equation in this form helps us identify the constants that are crucial for using the quadratic formula. Let's take the example from the exercise. The original equation given was \(x^2 - 2x = 1\). To bring this to standard form, we rearrange the terms so that one side of the equation is zero: \(x^2 - 2x - 1 = 0\).

This arrangement makes it clear that \(a=1\), \(b=-2\), and \(c=-1\). Recognizing these coefficients is a first and important step in solving the equation using the quadratic formula. Ensuring the equation is in standard form is critical for finding its solutions accurately.
Solving Quadratic Equations
Solving quadratic equations involves finding the values of \(x\) that satisfy the condition \(ax^2 + bx + c = 0\). Depending on the nature of the equation, various methods can be applied, but one of the most universal methods is using the quadratic formula.

The given quadratic equation from the exercise was \(x^2 - 2x = 1\). First, you convert this equation to its standard form, which results in \(x^2 - 2x - 1 = 0\). With the equation set up correctly, you then identify the coefficients: \(a = 1\), \(b = -2\), and \(c = -1\).

Substituting these values into the quadratic formula:\[x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \, \cdot\, 1 \, \cdot\, (-1)}}{2 \, \cdot \, 1}\]After working through the algebra, \(x = 1 \pm \sqrt{2}\) are the solutions. This implies that the values of \(x\) that satisfy the original equation are \(1 + \sqrt{2}\) and \(1 - \sqrt{2}\).

Solving these equations might seem complex initially, but with practice, identifying the form, substituting into the formula, and simplifying the terms can be done routinely, providing consistent results for any quadratic equation.

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Most popular questions from this chapter

Use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. You are choosing between two texting plans. Plan A has a monthly fee of \(\$ 15\) with a charge of \(\$ 0.08\) per text. Plan \(\mathbf{B}\) has a monthly fee of \(\$ 3\) with a charge of \(\$ 0.12\) per text. How many text messages in a month make plan A the better deal?

Use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. An elevator at a construction site has a maximum capacity of 3000 pounds. If the elevator operator weighs 245 pounds and each cement bag weighs 95 pounds, how many bags of cement can be safely lifted on the elevator in one trip?

If you are given a quadratic equation, how do you determine which method to use to solve it?

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