/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 81 Find each product. $$(2 x+y+1)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find each product. $$(2 x+y+1)^{2}$$

Short Answer

Expert verified
The product of \( (2x + y + 1)^{2} \) is \( 4x^{2} + 4xy + 2x + y^{2} + 2y + 1\).

Step by step solution

01

Rewrite the expression

Rewrite the expression \( (2x + y + 1)^{2} \) as \( (2x + y + 1) * (2x + y + 1) \) to clearly show that it's a product of two identical expressions.
02

Expand using the binomial theorem

The binomial theorem shows the multiplication of two identical binomials. We can apply this theorem here: \( (2x + y + 1)*(2x + y + 1) \). The result is \( (2x)* (2x) + 2 * (2x)* (y) + 2 * (2x)* (1) + (y)* (y) + 2 * (y)* (1) + (1)* (1) \).
03

Simplification

Now simplify the result from step 2. It will be \( 4x^{2} + 4xy + 2x + y^{2} + 2y + 1\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.