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91Ó°ÊÓ

Factor completely, or state that the polynomial is prime. $$x^{2}+64$$

Short Answer

Expert verified
The polynomial \(x^{2}+64\) is prime.

Step by step solution

01

Identify the polynomial

Given the polynomial \(x^{2}+64\).
02

Testing for factorability

To check if a polynomial can be factored, try using common factoring techniques such as finding common factors, grouping, or testing if it is a perfect square trinomial. In this case, no common factors exist and it is not a perfect square trinomial. The polynomial is a binomial. Notice if the binomial is a difference of squares, or a sum of squares in this case.
03

Factoring the polynomial

In algebra, a sum of squares such as \(x^{2}+64\) cannot be factored over the set of real numbers. Therefore, the polynomial \(x^{2}+64\) is prime because it cannot be factored.

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