/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Solve each absolute value inequa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each absolute value inequality. $$|5 x-2|>13$$

Short Answer

Expert verified
The solution to the inequality \(|5x - 2| > 13\) is \(x < -2.2\) or \(x > 3\).

Step by step solution

01

Set up two separate inequalities

An absolute value inequality \(|a| > b\) can be split into two separate inequalities: \(a < -b\) or \(a > b\). So, the given inequality \(|5x - 2| > 13\) will become \(5x - 2 < -13\) or \(5x - 2 > 13\). These two cases correspond to the fact that any number that's farther away from 0 than 13 on the number line is either less than -13 or greater than 13.
02

Solve each inequality separately

For the first inequality, \(5x - 2 < -13\), add 2 to both sides to isolate \(5x\), giving \(5x < -11\). Then, divide both sides by 5 to solve for \(x\), getting \(x < -2.2\). For the second inequality, \(5x - 2 > 13\), once again add 2 to both sides to yield \(5x > 15\), and then divide by 5, yielding \(x > 3\).
03

Write the solution

The solutions to the original inequality are the solutions to these two separate inequalities. Since \(x\) has to satisfy the original inequality, the final solution is \(x < -2.2\) or \(x > 3\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.