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Solve each absolute value inequality. $$\left|\frac{2 x+6}{3}\right|<2$$

Short Answer

Expert verified
The solution to the inequality is \(x \in (-6,0)\) or all numbers that are greater than -6 but less than 0

Step by step solution

01

Setting Up the Inequalities

Since the absolute value is less than a number, we will develop two inequalities. First, we keep the inside of the absolute value as it is and then compare it with the number at the right hand side, which is 2:\[\frac{2x+6}{3}<2\]Second, we reverse the sign of the expression inside the absolute value, and also reverse the inequality sign:\[-\frac{2x+6}{3}<2\]
02

Solve the First Inequality

\[\frac{2x+6}{3}<2\]To get rid of the fraction, multiply both sides by 3:\[2x+6<6\]Subtract 6 from both sides:\[2x<0\]Finally, divide both sides by 2 to isolate x:\[x<0\]
03

Solve the Second Inequality

To solve the second inequality, the steps are almost the same, but keeping in mind of the negative sign at the start:\[-\frac{2x+6}{3}<2\]Multiply both sides by 3:\[-2x-6<6\]Add 6 to both sides:\[-2x<12\]Divide both sides by -2 (and remember when you divide or multiply an inequality by a negative number, the inequality sign flips):\[x>-6\]
04

Combine the Inequalities

Both inequalities have to be satisfied, so combine them:\[x>-6 \text{ and } x<0\]This means that x can be any number that is greater than -6 but less than 0.

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