/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Solve each quadratic equation by... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each quadratic equation by the square root property. $$5 x^{2}+1=51$$

Short Answer

Expert verified
The solution to the equation is \(x = \sqrt{10}\) and \(x = -\sqrt{10}\)

Step by step solution

01

Simplify the equation

To simplify the equation and isolate the square term on one side of the equation, we subtract 1 from both sides of the given equation. We therefore obtain:\[5x^2 = 51 - 1 = 50\]
02

Isolate the square term

Now, to fully isolate the square term \(x^2\), we divide every term of the equation by 5 to obtain:\[x^2 = \frac{50}{5} = 10\]
03

Apply the square root property

Applying the square root property to our equation, we find the two potential values for \(x\). Remember, if \(x^2 = a\), then \(x = \sqrt{a}\) or \(x = -\sqrt{a}\). Thus we get:\[x = \sqrt{10}\] or \[x = -\sqrt{10}\]

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