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Factor each trinomial, or state that the trinomial is prime. $$x^{2}-4 x-5$$

Short Answer

Expert verified
The factored form of the trinomial \(x^{2}-4 x-5\) is \((x - 5)(x + 1)\)

Step by step solution

01

Identify the coefficients of the trinomial

Extract the coefficients of the given trinomial. In the given trinomial \(x^{2}-4 x-5\), \( a \) is 1, \( b \) is -4, and \( c \) is -5.
02

Find the factors of c

Find two numbers that multiply to -5 (the value of c), and that add up to -4 (the value of b). In this case, these two numbers would be -5 and 1, since (-5)*1 = -5 and (-5)+1 = -4.
03

Write the trinomial as a product of binomials

After finding the two numbers, write the trinomial as a product of two binomials. The trinomial \(x^{2}-4 x-5\) factors to become \((x - 5)(x + 1)\).

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