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Factor completely. $$x^{4}-10 x^{2} y^{2}+9 y^{4}$$

Short Answer

Expert verified
\((x^{2} - 3y^{2})^{2}\)

Step by step solution

01

Identify the squares

Each term in the equation \(x^{4}-10 x^{2} y^{2}+9 y^{4}\) is a square. The first term \(x^{4}\) is \((x^{2})^{2}\), the last term \(9 y^{4}\) is \((3y^{2})^{2}\) and the middle term \(10 x^{2} y^{2}\) is \(2*(x^{2})*(3y^{2})\). This confirms that the equation can be written in the form of a perfect square trinomial \(a^{2} - 2ab + b^{2}\).
02

Write equation as a perfect square trinomial

From Step 1, we have \(a = x^{2}\) and \(b = 3y^{2}\). Substituting these into the formula of the perfect square trinomial, we get: \((x^{2})^{2} - 2*x^{2}*3y^{2} + (3y^{2})^{2}\)
03

Factor the perfect square trinomial

The equation, being already identified as a perfect square trinomial, can be factored into \((a - b)^{2}\), which turns out to be \((x^{2} - 3y^{2})^{2}\)
04

Factor further (if possible)

The expression \((x^{2} - 3y^{2})^{2}\) itself cannot be factored further using integers because it is a difference of squares where the square root of one of the squares is not an integer.

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