/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Determine the equation in standa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the equation in standard form of the parabola that satisfies the given conditions. Focus at (-2,0)\(;\) vertex at (0,0)

Short Answer

Expert verified
The equation of the parabola in standard form that satisfies the given conditions is \(x = -2y^2\).

Step by step solution

01

Determine the direction of the parabola

A parabola is defined as the set of all points equidistant from a point (the focus) and a line (the directrix). Here, since the vertex is the origin (0,0), and the focus is at (-2,0), this implies that the parabola opens to the left.
02

Find the value of \(a\)

We know that the focus of the parabola can be found using the formula \((-a,0)\) where 'a' is the distance from the vertex to the focus, opening left or right. Here, the focus (-2,0) is given so 'a' value is -2.
03

Substitute the value of \(a\)

Now we substitute the value of 'a' into the equation \(x = ay^2\), which we identified based on the direction of the parabola. So, \(x = -2y^2\). This is the equation of the parabola in standard form.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertex Form of a Parabola
Understanding the vertex form of a parabola is a crucial stepping stone in learning about parabolas. The vertex form is particularly useful because it can easily show us the vertex, giving insights into the parabola's shape and direction.

A parabola's vertex form is given by the equation:
  • \( y = a(x-h)^2 + k \)
Here,
  • \( (h, k) \) is the vertex of the parabola.
  • \( a \) indicates the direction and width of the parabola. If \( a > 0 \), the parabola opens upward; if \( a < 0 \), it opens downward.
In cases where the parabola is horizontal, the vertex form can also appear as \( x = a(y-k)^2 + h \).

This alternative form would also reflect the change in orientation, emphasizing the point that either variable could be expressed in terms of the other. Understanding which form to use helps in graphing parabolas accurately.
Focus of a Parabola
The focus of a parabola is a point from which distances are measured in creating the parabola's defining property. Each point on the parabola is equidistant from the focus and the corresponding directrix.

Let's break that down. If you imagine a fixed point (focus) and a line (directrix), the parabola consists of all points where the distances to the focus and the directrix are equal. This definition holds great geometric significance.
  • The focus provides a key link to determining how the parabola opens. For the equation \( x = ay^2 \), as given in the exercise, the focus would determine its horizontal orientation.
  • In our specific case, the focus at (-2,0) hints that the vertex at (0,0) makes our parabola open to the left.
Knowing how to identify the focus, particularly in relation to the vertex and the directrix, is fundamental for both graphing and equation derivations.
Standard Form of Parabola
The standard form of a parabola's equation offers a streamlined, accessible approach to defining and understanding the parabola's properties. The equation's general structure differs slightly based on whether the parabola is oriented vertically or horizontally.

For vertically oriented parabolas, the standard form is:
  • \( y = ax^2 + bx + c \)
For horizontal parabolas, such as the one in the problem, the form typically appears as:
  • \( x = ay^2 + by + c \)
Specific to our exercise, where we're given \( x = -2y^2 \), the absence of linear/directional \( b \) and constant \( c \) terms in this derived equation indicates a straightforward horizontal orientation without shifts.

This form simplifies the process of identifying key aspects such as the vertex and direction. By becoming comfortable with the standard form, students can more easily transition between different portrayals of parabolas and solve related problems efficiently.

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Most popular questions from this chapter

A lithotripter is a device that breaks up kidney stones by propagating shock waves through water in a chamber that has an elliptical cross-section. High- frequency shock waves are produced at one focus, and the patient is positioned in such a way that the kidney stones are at the other focus. On striking a point on the boundary of the chamber, the shock waves are reflected to the other focus and break up the kidney stones. Find the coordinates of the foci if the center of the ellipse is at the origin, one vertex is at \((6,0),\) and one endpoint of the minor axis is at (0,-2.5)

Determine the equation in standard form of the ellipse that satisfies the given conditions. One endpoint of minor axis at (7,-4)\(;\) center at (7,-8) major axis of length 12

This set of exercises will draw on the ideas presented in this section and your general math background. The hyperbolas \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) and \(\frac{y^{2}}{a^{2}}-\frac{x^{2}}{b^{2}}=1\) are called conjugate hyperbolas. Show that one hyperbola is the reflection of the other in the line \(y=x\)

This set of exercises will draw on the ideas presented in this section and your general math background. There are hyperbolas other than the types studied in this section. For example, some hyperbolas satisfy an equation of the form \(x y=c,\) where \(c\) is a nonzero constant. In which quadrant(s) of the coordinate plane does the hyperbola with equation \(x y=10\) lie? the hyperbola with equation \(x y=-10 ?\)

Without trying to graph, show that there are no real number values \(x\) and \(y\) such that \(x^{2}+2 y^{2}+1=0\).

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