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Find the inverse of \(A^{2}\) and the inverse of \(A^{3}\) (where \(A^{2}\) is the product AA and \(A^{3}\) is the product \(\left(A^{2}\right) A\) ). $$A=\left[\begin{array}{rr}2 & 1 \\\0 & -1\end{array}\right]$$

Short Answer

Expert verified
Therefore, the inverse of \(A^{2}\) is \([0.25, 0; 0, 1]\) and the inverse of \(A^{3}\) is \([0.125, 0.5; 0, 1]\).

Step by step solution

01

Compute the inverse of matrix A

First, the determinant of A, denoted as det(A), needs to be computed. For A = [2, 1; 0, -1], det(A) = 2*(-1) - (0)*1 = -2. The adjugate of A, adj(A), then needs to be calculated. For any 2x2 matrix [a, b; c, d], adj([a, b; c, d]) = [d, -b; -c, a]. Therefore, adj(A) = [-1, -1; 0, 2]. Substituting these in the formula for A_inv gives A_inv = 1/det(A) * adj(A) = -1/2 * [-1, -1; 0, 2] = [0.5, 0.5; 0, -1].
02

Compute the inverse of \(A^{2}\)

By definition, \(A^2 = AA\). Therefore, \((A^{2})^{-1}\) = \((AA)^{-1}\). Using the property that (AB)^{-1}=B^{-1}A^{-1}, \((A^{2})^{-1}\) = \(A^{-1} * A^{-1}\) = [0.5, 0.5; 0, -1] * [0.5, 0.5; 0, -1] = [0.25, 0; 0, 1].
03

Compute the inverse of \(A^{3}\)

By definition, \(A^3 = (A^{2})A\). Therefore, \((A^{3})^{-1}\) = \(((A^{2})A)^{-1}\). Using the property that (AB)^{-1}=B^{-1}A^{-1}, \((A^{3})^{-1}\) = \(A^{-1} * (A^{2})^{-1}\) = [0.5, 0.5; 0, -1] * [0.25, 0; 0, 1] = [0.125, 0.5; 0, 1].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse of a Matrix
The concept of an inverse of a matrix is akin to division for numbers. In mathematics, particularly in linear algebra, finding the inverse of a matrix is equivalent to finding a reciprocal such that when the original matrix is multiplied by its inverse, the resulting product is the identity matrix. This identity matrix plays a role similar to the number 1 in multiplication for real numbers.

Not all matrices have inverses, but for those that do, the process begins by determining if the matrix is square (same number of rows and columns) and its determinant is not zero. The matrix must be square because nonsquare matrices do not have multiplicative inverses. The determinant being non-zero is crucial, as a zero determinant indicates the matrix is singular, meaning it does not have an inverse.

In the given exercise, the objective was to find the inverse of the matrices derived from the original square matrix, 'A'. We employed the property that \( (AB)^{-1} = B^{-1}A^{-1} \) to simplify the process. Essentially, to find the inverse of a matrix raised to a power, you take the inverse of the original matrix and then raise that to the same power.
Determinant of a Matrix
The determinant is a scalar value that can be computed from the elements of a square matrix. It provides important information about a matrix, such as whether it is invertible or not. If the determinant of a matrix is zero, the matrix does not have an inverse and is said to be singular. Conversely, a non-zero determinant guarantees the existence of an inverse.

For a 2x2 matrix \(A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right]\), the determinant \(det(A)\) is calculated as \(ad - bc\). In our exercise, we calculated the determinant of matrix A, which was the first step in determining the matrix's invertibility. A non-zero determinant is the green light signaling that the inverse of the matrix can indeed be found using the adjugate and dividing by the determinant.
Adjugate of a Matrix
The adjugate, or classical adjoint, of a matrix is a transformed matrix where each element is replaced by the corresponding cofactor, and then a subsequent transposition of the resulting matrix is performed. For a 2x2 matrix, the process is simplified as the adjugate can be directly obtained by swapping the positions of the elements on the main diagonal and then changing the sign of the off-diagonal elements.

In the context of our example, the adjugate of matrix A, \(adj(A)\), was obtained after calculating the determinant. It’s a necessary step for computing the inverse of a matrix through the formula \(A^{-1} = \frac{1}{det(A)} * adj(A)\). The adjugate plays a fundamental role in finding the inverse because it's related to the concept of minors and cofactors, which help to understand the system of linear equations represented by the matrix. It is important to recognize the utility of the adjugate matrix as it provides a way to solve for the inverse of a matrix without having to perform more complex operations like Gaussian elimination.

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Most popular questions from this chapter

In this set of exercises, you will use the method of solving linear systems using matrices to study real-world problems. An electronics store carries two brands of video cameras. For a certain week, the number of Brand A video cameras sold was 10 less than twice the number of Brand B cameras sold. Brand A cameras cost \(\$ 200\) and Brand \(B\) cameras cost \(\$ 350 .\) If the total revenue generated that week from the sale of both types of cameras was \(\$ 16,750,\) how many of each type were sold?

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In this set of exercises, you will use the method of solving linear systems using matrices to study real-world problems. Electrical Engineering An electrical circuit consists of three resistors connected in series. The formula for the total resistance \(R\) is given by \(R=R_{1}+R_{2}+R_{3},\) where \(R_{1}, R_{2},\) and \(R_{3}\) are the resistances of the individual resistors. In a circuit with two resistors \(A\) and \(B\) connected in series, the total resistance is 60 ohms. The total resistance when \(B\) and \(C\) are connected in series is 100 ohms. The sum of the resistances of \(B\) and \(C\) is 2.5 times the resistance of \(A\). Find the resistances of \(A, B\), and \(C\).

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