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Use Gaussian elimination to solve the system of linear equations. If there is no solution, state that the system is inconsistent. $$\left\\{\begin{array}{rr} x-2 y-5 z= & -3 \\ 3 x-6 y-7 z= & 1 \\ -2 x+4 y+12 z= & -4 \end{array}\right.$$

Short Answer

Expert verified
The system of equations is inconsistent, and has no solutions

Step by step solution

01

Set Up the Augmented Matrix

From the system of equation given, we create an augmented matrix by writing the coefficients of \(x\), \(y\), \(z\) and the constants in matrix form as follows: \[ \left[ \begin{array}{ccc|c} 1 & -2 & -5 & -3 \\ 3 & -6 & -7 & 1 \\ -2 & 4 & 12 & -4 \end{array} \right] \]
02

Perform Gaussian Elimination

We need to convert this to row-echelon form. Start by subtracting the first row three-times from the second row and adding twice the first row to the third row. This yields: \[ \left[ \begin{array}{ccc|c} 1 & -2 & -5 & -3 \\ 0 & 0 & 8 & 10 \\ 0 & 0 & 2 & -2 \end{array} \right] \] Next, we divide the second row by 8 and divide the third row by 2 to get: \[ \left[ \begin{array}{ccc|c} 1 & -2 & -5 & -3 \\ 0 & 0 & 1 & 1.25 \\ 0 & 0 & 1 & -1 \end{array} \right] \] Finally, we subtract the third row from the second row, and add five times the second row to the first row, which yields: \[ \left[ \begin{array}{ccc|c} 1 & -2 & 0 & 3.25 \\ 0 & 0 & 1 & 1.25 \\ 0 & 0 & 0 & 2.25 \end{array} \right] \]
03

Analyze the Result

The last row of the matrix in row-echelon form represents the equation 0 = 2.25, which makes no sense. Thus, we can conclude that the system is inconsistent, and there is no solution for it.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Linear Equations
Understanding a system of linear equations is foundational in algebra and many areas of mathematics. It consists of two or more equations involving the same set of variables. The goal is to find the values of these variables that satisfy all equations in the system simultaneously. A system may have exactly one solution, infinitely many solutions, or no solution at all. One solution corresponds to a single point where the equations intersect, while infinitely many solutions indicate that the equations describe the same line or plane. When there's no solution, the equations represent parallel lines that never intersect, which leads us to an inconsistent system.

The system provided in the exercise is a classic example, where we're looking for values of x, y, and z that satisfy all three given equations. To solve such systems, one common method is Gaussian elimination, which systematically reduces the system to a simpler form to make the solution evident or to show that no solution exists.
Augmented Matrix
An augmented matrix is a compact, array-like representation of a system of linear equations. It comprises the coefficients of the variables and the constants from each equation, placed in columns side by side with a vertical bar separating the constants. This format is particularly useful for performing algebraic manipulations while preserving the equations' relationships.

For the given exercise, we have three linear equations which we convert into an augmented matrix by listing coefficients of x, y, and z alongside their corresponding constant values. The resulting matrix serves as the starting point for Gaussian elimination, and it's essential for visualizing the steps we will take to simplify the system. By focusing on the coefficients and constants, we eliminate the variables' symbols, making calculations more efficient.
Row-Echelon Form
Row-echelon form is a staircase-shaped pattern that results from applying Gaussian elimination to an augmented matrix. The characteristics of row-echelon form include having all nonzero rows above any rows of all zeroes, and each leading coefficient (also known as a pivot) is to the right of the leading coefficient of the row above it. Moreover, pivot columns should be filled with zeros below the leading coefficient.

Demanding this specific form makes it easier to determine if the system has one solution, many solutions, or none. By transforming the given exercise's augmented matrix into row-echelon form, we systematically simplify the system, revealing the nature of the solution. The lower the leftmost nonzero entry is in a row, the clearer it becomes whether the variables can be solved for or if the system is inconsistent.
Inconsistent System
An inconsistent system of equations is one where no set of values satisfies all equations simultaneously. This happens when the equations represent parallel lines or planes that never intersect, implying there is no common solution. Upon reaching row-echelon form during Gaussian elimination, an inconsistency is revealed through a row that translates to a false statement, such as 0 = a nonzero number.

In our exercise, after performing Gaussian elimination, the final matrix yields such a row indicating an inconsistency. The equation represented by the last row, 0x + 0y + 0z = 2.25, is impossible because it suggests that 0 equals some nonzero constant, which is a contradiction. Therefore, it confirms that the system of equations has no solution, and we accurately describe it as inconsistent.

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Most popular questions from this chapter

A farmer has 110 acres available for planting cucumbers and peanuts. The cost of seed per acre is \(\$ 5\) for cucumbers and \(\$ 6\) for peanuts. To harvest the crops, the farmer will need to hire some temporary help. It will cost the farmer \(\$ 30\) per acre to harvest the cucumbers and \(\$ 20\) per acre to harvest the peanuts. The farmer has \(\$ 300\) available for seed and \(\$ 1200\) available for labor. His profit is \(\$ 100\) per acre of cucumbers and \(\$ 125\) per acre of peanuts. How many acres of each crop should the farmer plant to maximize the profit?

Three students take courses at two different colleges, Woosamotta University \((\mathrm{WU})\) and Frostbite Falls Community College (FFCC). WU charges \(\$ 200\) per credit hour and FFCC charges \(\$ 120\) per credit hour. The number of credits taken by each student at each college is given in the following table. $$\begin{array}{|c|c|c|}\hline & {2}{c}\text { Credits } \\\\\text { Student } & \text { WU } & \text { FFCC } \\\\\hline 1 & 12 & 6 \\\2 & 3 & 9 \\\3 & 8 & 8 \\ \hline\end{array}$$ Use matrix multiplication to find the total tuition paid by cach student.

Apply elementary row operations to a matrix to solve the system of equations. If there is no solution, state that the system is inconsistent. $$\left\\{\begin{array}{c}x+2 y+z=-3 \\ 3 x+y-2 z=2 \\ 4 x+3 y-z=0\end{array}\right.$$

Answer the question pertaining to the matrices. $$A=\left[\begin{array}{ll}a & b \\\c & d \\\e & f\end{array}\right] \text { and } B=\left[\begin{array}{lll}g & h & i \\\j & k & l\end{array}\right]$$ Let \(Q=B A,\) and find \(q_{11}\) and \(q_{22}\) without performing the entire multiplication of matrix \(B\) by matrix \(A\).

The total revenue generated by a film comes from two sources: box-office ticket sales and the sale of merchandise associated with the film. It is estimated that for a very popular film such as Spiderman or Harry Potter, the revenue from the sale of merchandise is four times the revenue from ticket sales. Assume this is true for the film Spiderman, which grossed a total of \(\$ 3\) billion. Find the revenue from ticket sales and the revenue from the sale of merchandise.

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