/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Write the partial fraction decom... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the partial fraction decomposition of each rational expression. $$\frac{-x^{2}+3 x-9}{x^{3}-3 x^{2}}$$

Short Answer

Expert verified
The partial fraction decomposition of \(\frac{-x^{2}+3 x-9}{x^{3}-3 x^{2}}\) is \(\frac{-2}{x}\) + \(\frac{-3}{x-3}\)

Step by step solution

01

Factorize Denominator

Firstly, factorize the denominator. Here, the denominator \(x^{3}-3 x^{2}\) can be factorized to \(x^{2}(x-3)\).
02

Set Up Partial Fractions

We know that a rational function of the form \(\frac{P(x)}{Q(x)}\), where \(Q(x)\) is a factorized polynomial, can be written in partial fraction form as follows: \(\frac{A_1}{x}\) + \(\frac{A_2}{x-3}\) where \(A_1\) and \(A_2\) are constants to be determined.
03

Multiply Both Sides by \(x^{2}(x-3)\) and Simplify

If you multiply both sides of the equation \(\frac{-x^{2}+3 x-9}{x^{2}(x-3)}\) = \(\frac{A_1}{x}\) + \(\frac{A_2}{x-3}\) by \(x^{2}(x-3)\) and simplify, you get the following equation to solve for \(A_1\) and \(A_2\): \(-x^{2}+3x-9\) = \(A_1(x-3) + A_2x\).
04

Solve for \(A_1\) and \(A_2\)

To find the constants \(A_1\) and \(A_2\), set \(x=3\) and \(x=0\) respectively in the simplified equation. Solving for \(A_1\) and \(A_2\), you get \(A_1=-2\) and \(A_2=-3\).
05

Write the Final Answer

Substitute \(A_1\) and \(A_2\) into \(\frac{A_1}{x}\) + \(\frac{A_2}{x-3}\) to write the simplified expression: \(\frac{-2}{x}\) + \(\frac{-3}{x-3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorization of Polynomials
The first step in decomposing a rational expression into partial fractions is to factorize the denominator, which is itself a polynomial. Factorization of polynomials is a critical skill in algebra; it involves breaking down a complex polynomial into simpler polynomials that multiply together to give the original polynomial. This decomposition is akin to finding what numbers multiply together to give a particular number, just as 15 can be factorized into 3 and 5.

For example, the polynomial \(x^3-3x^2\) can be factored by recognizing a common factor in each term: \(x^2\). Factoring out this common multiplier, we get \(x^2(x-3)\), which lays the groundwork for the next steps in partial fraction decomposition. Effective factorization often requires recognizing patterns, such as the difference of squares, perfect square trinomials, or the sum/difference of cubes, and applying the appropriate factorization method.
Rational Expressions
Rational expressions are fractions in which both the numerator and the denominator are polynomials. To understand these, one must be familiar with both polynomials and the concept of fractions. A rational expression looks very similar to a fraction you might encounter in arithmetic, such as \(\frac{1}{2}\) or \(\frac{3}{4}\), but instead of numbers, you have expressions involving variables like x or y.

For instance, \(\frac{-x^2+3x-9}{x^3-3x^2}\) is a rational expression where the numerator is a polynomial of degree 2, and the denominator is of degree 3. These expressions can be simplified, added, subtracted, multiplied, and divided, using rules similar to numerical fractions but involving algebraic manipulation. In calculus and algebra, simplifying rational expressions through partial fraction decomposition paves the way for easier integration or solving of equations.
Algebraic Fractions
Algebraic fractions are the algebraic extension of arithmetic fractions. Much like the fractions you're used to, algebraic fractions can consist of numerators and denominators that are algebraic expressions. The partial fraction decomposition approach is a technique used to break down complex algebraic fractions into simpler ones that are easier to work with, whether for integration in calculus or solving equations.

In the context of the exercise \(\frac{-x^2+3x-9}{x^3-3x^2}\), we must decompose the complex algebraic fraction into forms like \(\frac{A_1}{x}\) and \(\frac{A_2}{x-3}\) where \(A_1\) and \(A_2\) are constants determined through algebraic techniques. The goal is to express the original complicated fraction as the sum of these simpler fractions, enabling easier mathematical manipulation. Understanding how to handle algebraic fractions is essential for success in advanced mathematics, as they form a basis for many more complex algebraic and calculus concepts.

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Most popular questions from this chapter

A farmer has 110 acres available for planting cucumbers and peanuts. The cost of seed per acre is \(\$ 5\) for cucumbers and \(\$ 6\) for peanuts. To harvest the crops, the farmer will need to hire some temporary help. It will cost the farmer \(\$ 30\) per acre to harvest the cucumbers and \(\$ 20\) per acre to harvest the peanuts. The farmer has \(\$ 300\) available for seed and \(\$ 1200\) available for labor. His profit is \(\$ 100\) per acre of cucumbers and \(\$ 125\) per acre of peanuts. How many acres of each crop should the farmer plant to maximize the profit?

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Find the decoding matrix for each encoding matrix. $$\left[\begin{array}{ll}1 & -3 \\\1 & -2\end{array}\right]$$

A furniture manufacturer makes three different picces of furniture, each of which utilizes some combination of fabrics \(A, B,\) and \(C .\) The yardage of each fabric required for each piece of furniture is given in matrix \(F\). Fabric A Fabric B Fabric C (yd) \(\quad\) (yd) \(\quad\) (yd) \(\begin{array}{r}\text { Sofa } \\ \text { Loveseat } \\ \text { Chair }\end{array}\left[\begin{array}{ccc}10.5 & 2 & 1 \\ 8 & 1.5 & 1 \\ 4 & 1 & 0.5\end{array}\right]=F\) The cost of each fabric (in dollars per yard) is given in matrix \(C\).$$\begin{array}{l}\text { Fabric A } \\\\\text { Fabric B } \\\\\text { Fabric C }\end{array}\left[\begin{array}{r}10 \\\6 \\\5\end{array}\right]=C$$ Find the total cost of fabric for each piece of furniture.

If \(A=\left[\begin{array}{ccc}3 & 16 & 5 \\ 4 & 3 & 6\end{array}\right]\) and \(B=\left[\begin{array}{ccc}1 & a^{2}-2 a-7 & 2 \\ b^{2}-5 b-4 & 1 & 3\end{array}\right],\) for what values of \(a\) and \(b\) does \(A-2 B=\left[\begin{array}{lll}1 & 0 & 1 \\ 0 & 1 & 0\end{array}\right] ?\)

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