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Use Gaussian elimination to solve the system of linear equations. If there is no solution, state that the system is inconsistent. $$\left\\{\begin{aligned} x+2 y &=0 \\ -2 x+4 y+8 z &=8 \\ 3 x &-3 z=-9 \end{aligned}\right.$$

Short Answer

Expert verified
The solution to the system of linear equations is \(x = 2, y = 1, z = 1/3\).

Step by step solution

01

Write the given system in augmented matrix form

The system of equations can be written as an augmented matrix as follows: \[ \left[ \begin{array}{ccc|c} 1 & 2 & 0 & 0 \ -2 & 4 & 8 & 8 \ 3 & 0 & -3 & -9 \end{array} \right] \] Each row of the matrix corresponds to one equation, and each column (except for the rightmost column after the bar) corresponds to coefficients of one variable.
02

Perform row operations to bring the matrix into row-echelon form or reduced row-echelon form

Begin with swapping row 1 and row 2, so that 1 is the left-most non-zero element, then add 2 times the new first row to the second row, and subtract 3 times the new first row from the third row: \[ \left[ \begin{array}{ccc|c} -2 & 4 & 8 & 8 \ 0 & 4 & 8 & 8 \ 0 & -6 & -3 & -9 \end{array} \right] \] Then, divide the first row by -2, the second row by 4, and the third row by -3: \[ \left[ \begin{array}{ccc|c} 1 & -2 & -4 & -4 \ 0 & 1 & 2 & 2 \ 0 & 2 & 1 & 3 \end{array} \right] \] Finally, subtract 2 times the second row from the third row to make the matrix into row-echelon form: \[ \left[ \begin{array}{ccc|c} 1 & -2 & -4 & -4 \ 0 & 1 & 2 & 2 \ 0 & 0 & -3 & -1 \end{array} \right] \]
03

Interpret the resulting matrix

Each row of the resulting matrix can be translated back into an equation. The reduced row-echelon form of the matrix corresponds to the system of equations: \(x - 2y - 4z = -4\), \(y + 2z = 2\), and \(-3z = -1\), which gives \(z = 1/3\), \(y = 1\), and \(x = 2\). These are the solutions to the system of equations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Linear Equations
A system of linear equations consists of multiple linear equations that are solved together in order to find values for a set of variables that satisfy all the equations simultaneously. Each equation represents a straight line in two-dimensional space or a plane in three-dimensional space, and the solution of a system is the point or set of points where these lines or planes intersect.

For example, in a system with three variables, the solution is the point in three-dimensional space where all three planes corresponding to the equations intercept. When utilizing Gaussian elimination to solve such a system, the goal is to use algebraic manipulation to simplify the equations to the point where the solution is clear. If the system is inconsistent, it means that there is no set of values for the variables that can satisfy all the equations, often because the planes represented by the equations do not intersect at a single point.
Augmented Matrix
An augmented matrix is a compact way to represent a system of linear equations. It's constructed by writing the coefficients of the variables in a grid, with each row representing an equation and each column representing a variable. A vertical bar is used to separate the coefficients from the constants on the right-hand side of each equation.

In our exercise example, the augmented matrix makes it easy to perform row operations as part of the Gaussian elimination process. Operations like swapping rows, multiplying rows by non-zero constants, and adding multiples of one row to another are used to simplify the matrix, eventually leading to a form from which the solutions can easily be read.
Row-Echelon Form
Row-echelon form is a stage in Gaussian elimination where the augmented matrix has been simplified to a point where each successive row has more leading zeros than the previous row. The leading entry of each nonzero row (after the leading zeros) is strictly to the right of the leading entry in the row above. These leading entries are often made to be 1 (called a leading 1) to simplify the process further.

In this form, it becomes easy to 'read off' the solutions or to perform back-substitution to find the values of the variables. If a row has all zeros to the left of the bar and a nonzero number to the right, it indicates an inconsistency, meaning there is no solution. If there are at least as many equations as variables, and row-echelon form is reached without encountering such an inconsistency, one can typically find a unique solution to the system.

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Most popular questions from this chapter

At a certain gas station, the prices of regular and high-octane gasoline are \(\$ 2.40\) per gallon and \(\$ 2.65\) per gallon, respectively. Use matrix scalar multiplication to compute the cost of 12 gallons of each type of fuel.

Three students take courses at two different colleges, Woosamotta University \((\mathrm{WU})\) and Frostbite Falls Community College (FFCC). WU charges \(\$ 200\) per credit hour and FFCC charges \(\$ 120\) per credit hour. The number of credits taken by each student at each college is given in the following table. $$\begin{array}{|c|c|c|}\hline & {2}{c}\text { Credits } \\\\\text { Student } & \text { WU } & \text { FFCC } \\\\\hline 1 & 12 & 6 \\\2 & 3 & 9 \\\3 & 8 & 8 \\ \hline\end{array}$$ Use matrix multiplication to find the total tuition paid by cach student.

Find the decoding matrix for each encoding matrix. $$\left[\begin{array}{ll}1 & -3 \\\1 & -2\end{array}\right]$$

For the given matrices \(A, B,\) and \(C,\) evaluate the indicated expression. $$\begin{aligned}&A=\left[\begin{array}{ll}4 & 1 \\\0 & 2 \\\5 & 1\end{array}\right] ; \quad B=\left[\begin{array}{rr}4 & 3 \\\\-6 & 2 \\\3 & -1\end{array}\right]\\\&C=\left[\begin{array}{rrr}1 & 2 & 3 \\\\-2 & -3 & -1 \\\3 & 1 & 2\end{array}\right] ; \quad C(B-A)\end{aligned}$$

A chemist wishes to make 10 gallons of a \(15 \%\) acid solution by mixing a \(10 \%\) acid solution with a \(25 \%\) acid solution. (a) Let \(x\) and \(y\) denote the total volumes (in gallons) of the \(10 \%\) and \(25 \%\) solutions, respectively. Using the variables \(x\) and \(y,\) write an equation for the total volume of the \(15 \%\) solution (the mixture). (b) Using the variables \(x\) and \(y,\) write an equation for the total volume of acid in the mixture by noting that Volume of acid in \(15 \%\) solution \(=\) volume of acid in \(10 \%\) solution \(+\) volume of acid in \(25 \%\) solution. (c) Solve the system of equations from parts (a) and (b), and interpret your solution. (d) Is it possible to obtain a \(5 \%\) acid solution by mixing a \(10 \%\) solution with a \(25 \%\) solution? Explain without solving any equations.

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